# Ex 9.4, 21 - Chapter 9 Class 12 Differential Equations

Last updated at Dec. 10, 2019 by Teachoo

Last updated at Dec. 10, 2019 by Teachoo

Transcript

Ex 9.4, 21 In a bank, principal increases continuously at the rate of 5% per year. An amount of Rs 1000 is deposited with this bank , how much will it worth after 10 years (๐^0.5=1.648) Let Principle = p Given, principle increases at rate 5% per year โด ๐๐/๐๐ก = 5% ร p โด ๐๐/๐๐ก = 5/100 ร p ๐๐/๐ = 1/20 dt Integrating both sides โซ1โ๐๐/๐ = 1/20 โซ1โ๐๐ก log p = ๐ก/20 + log c log p โ log c = 0.05t log ๐/๐ = 0.05t ๐/๐ = e0.05t Now, given that an amount of Rs 1000 is deposited with this bank Putting T = 0, P = 1000 in (1) 1000/๐ถ= e0.05 ร 0 1000/๐ถ= e0 1000/๐ถ= 1 ๐= 1000 โฆ(1) Now, we need to how much is the amount after 10 years So, Putting t = 10 & c = 1000 in (1) ๐/1000 = e0.05(10) ๐/1000 = ๐^0.5 ๐/1000 = 1.648 p = 1648 โด The amount is Rs 1648 after 10 years. (Given e0.5 = 1.648)

Ex 9.4

Ex 9.4, 1
Important

Ex 9.4, 2

Ex 9.4, 3

Ex 9.4, 4 Important

Ex 9.4, 5

Ex 9.4, 6

Ex 9.4, 7

Ex 9.4, 8

Ex 9.4, 9 Important

Ex 9.4, 10 Important

Ex 9.4, 11

Ex 9.4, 12

Ex 9.4, 13

Ex 9.4, 14

Ex 9.4, 15 Important

Ex 9.4, 16

Ex 9.4, 17

Ex 9.4, 18

Ex 9.4, 19 Important

Ex 9.4, 20 Important

Ex 9.4, 21 You are here

Ex 9.4, 22 Important

Ex 9.4, 23

Chapter 9 Class 12 Differential Equations

Serial order wise

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.