# Ex 9.4, 21 - Chapter 9 Class 12 Differential Equations (Term 2)

Last updated at Dec. 10, 2019 by Teachoo

Last updated at Dec. 10, 2019 by Teachoo

Transcript

Ex 9.4, 21 In a bank, principal increases continuously at the rate of 5% per year. An amount of Rs 1000 is deposited with this bank , how much will it worth after 10 years (๐^0.5=1.648) Let Principle = p Given, principle increases at rate 5% per year โด ๐๐/๐๐ก = 5% ร p โด ๐๐/๐๐ก = 5/100 ร p ๐๐/๐ = 1/20 dt Integrating both sides โซ1โ๐๐/๐ = 1/20 โซ1โ๐๐ก log p = ๐ก/20 + log c log p โ log c = 0.05t log ๐/๐ = 0.05t ๐/๐ = e0.05t Now, given that an amount of Rs 1000 is deposited with this bank Putting T = 0, P = 1000 in (1) 1000/๐ถ= e0.05 ร 0 1000/๐ถ= e0 1000/๐ถ= 1 ๐= 1000 โฆ(1) Now, we need to how much is the amount after 10 years So, Putting t = 10 & c = 1000 in (1) ๐/1000 = e0.05(10) ๐/1000 = ๐^0.5 ๐/1000 = 1.648 p = 1648 โด The amount is Rs 1648 after 10 years. (Given e0.5 = 1.648)

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Ex 9.4, 23 (MCQ)

Chapter 9 Class 12 Differential Equations (Term 2)

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.