


Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class
Last updated at May 29, 2023 by Teachoo
Ex 9.2, 1 Verify that the given functions (explicit or implicit) is a solution of the corresponding differential equation : π¦=π^π₯+1 : π¦^β²β²βπ¦^β²=0 π=π^π+π Now, π^β²=ππ¦/ππ₯=π/ππ₯Solving L.H.S π^β²β²βπ^β² =π^π₯βπ^π₯ =0 = R.H.S Hence verified. Solving L.H.S π^β²β²βπ^β² =π^π₯βπ^π₯ =0 = R.H.S Hence verified.