# Ex 9.4, 14 - Chapter 9 Class 12 Differential Equations (Term 2)

Last updated at Nov. 14, 2019 by Teachoo

Last updated at Nov. 14, 2019 by Teachoo

Transcript

Ex 9.4, 14 For each of the differential equations in Exercises 11 to 14, find a particular solution satisfying the given condition : 𝑑𝑦𝑑𝑥=𝑦 tan 𝑥;𝑦=1 When 𝑥=0 𝑑𝑦𝑑𝑥=𝑦 tan x 𝑑𝑦𝑦= tan x dx Integrating both sides 𝑑𝑦𝑦 = tan𝑥 𝑑𝑥 log 𝑦 = log sec𝑥+ log𝑐 log 𝑦 = log (c sec x) y = c sec x Put x = 0 and y = 1 1 = C Sec 0 1 = C Put value of C in (1) y = 1 × sec x y = sec x

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Ex 9.4, 23 (MCQ)

Chapter 9 Class 12 Differential Equations (Term 2)

Serial order wise

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.