
Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class
Ex 9.3
Ex 9.3, 2
Ex 9.3, 3
Ex 9.3, 4 Important
Ex 9.3, 5
Ex 9.3, 6
Ex 9.3, 7 Important
Ex 9.3, 8
Ex 9.3, 9 Important
Ex 9.3, 10 Important
Ex 9.3, 11 Important
Ex 9.3, 12
Ex 9.3, 13
Ex 9.3, 14 You are here
Ex 9.3, 15 Important
Ex 9.3, 16
Ex 9.3, 17 Important
Ex 9.3, 18
Ex 9.3, 19 Important
Ex 9.3, 20 Important
Ex 9.3, 21
Ex 9.3, 22 Important
Ex 9.3, 23 (MCQ)
Last updated at Aug. 11, 2023 by Teachoo
Ex 9.3, 14 For each of the differential equations in Exercises 11 to 14, find a particular solution satisfying the given condition : ππ¦/ππ₯=π¦ tanβ‘ π₯;π¦=1 When π₯=0 ππ¦/ππ₯=π¦ tanβ‘ x π π/π=γπππ§ π± ππ±γβ‘ Integrating both sides β«1βππ¦/π¦ = β«1βtanβ‘γπ₯ ππ₯γ log |π| = log |π¬ππβ‘π |+πππβ‘π log |π¦| = log (c sec x) y = c sec x (β΅ log π + log b = log πb) Put x = 0 and y = 1 1 = C Sec 0 1 = C Γ 1 C = 1 Put value of C in (1) y = 1 Γ sec x y = sec x