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Ex 9.4
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Ex 9.4, 14 You are here
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Ex 9.4, 23 (MCQ)
Last updated at March 16, 2023 by Teachoo
Ex 9.4, 14 For each of the differential equations in Exercises 11 to 14, find a particular solution satisfying the given condition : 𝑑𝑦𝑑𝑥=𝑦 tan 𝑥;𝑦=1 When 𝑥=0 𝑑𝑦𝑑𝑥=𝑦 tan x 𝑑𝑦𝑦= tan x dx Integrating both sides 𝑑𝑦𝑦 = tan𝑥 𝑑𝑥 log 𝑦 = log sec𝑥+ log𝑐 log 𝑦 = log (c sec x) y = c sec x Put x = 0 and y = 1 1 = C Sec 0 1 = C Put value of C in (1) y = 1 × sec x y = sec x