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Ex 9.3
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Ex 9.3, 23 (MCQ)
Last updated at Aug. 11, 2023 by Teachoo
Ex 9.3, 6 For each of the differential equations in Exercises 1 to 10, find the general solution : ππ¦/ππ₯=(1+π₯^2 )(1+π¦^2 )ππ¦/ππ₯=(1+π₯^2 )(1+π¦^2 ) dy = (1+π₯^2 )(1+π¦^2 ) dx π π/(π + π^π )= (1 + π^π) dx Integrating both sides. β«1βππ¦/(1 + π¦^2 ) = β«1β(1+π₯2)ππ₯ tanβ1 y = x + π^π/π + C (β«1β1/(1+π¦^2 ) dy = tanβ1 y)