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Last updated at May 29, 2018 by Teachoo
Transcript
Ex 9.4, 6 For each of the differential equations in Exercises 1 to 10, find the general solution : ππ¦/ππ₯=(1+π₯^2 )(1+π¦^2 ) ππ¦/ππ₯=(1+π₯^2 )(1+π¦^2 ) dy = (1+π₯^2 )(1+π¦^2 ) dx ππ¦/(1 + π¦^2 )= (1 + π₯^2) dx Integrating both sides. β«1βππ¦/(1 + π¦^2 ) = β«1β(1+π₯2)ππ₯ tanβ1 y = x + π^π/π + C
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