1. Chapter 6 Class 12 Application of Derivatives
  2. Serial order wise
  3. Ex 6.3

Ex 6.3,26 - Chapter 6 Class 12 Application of Derivatives

Last updated at May 29, 2018 by

Ex 6.3, 26 - Slope of normal to y = 2x2 + 3 sin x at x = 0 is - Finding slope of tangent/normal

Slide27.JPG

  1. Chapter 6 Class 12 Application of Derivatives
  2. Serial order wise

    3. Ex 6.3

    Ex 6.4 →
Ask Download

Transcript

Ex 6.3,26 The slope of the normal to the curve y = 2x2 + 3 sin x at x = 0 is (A) 3 (B) 1﷮3﷯ (C) – 3 (D) – 1﷮3﷯ Slope of tangent is 𝑑𝑦﷮𝑑𝑥﷯ 𝑦=2 𝑥﷮2﷯+3 sin﷮𝑥﷯ Differentiating w.r.t.𝑥 𝑑𝑦﷮𝑑𝑥﷯= 𝑑 2 𝑥﷮2﷯ +3 sin﷮𝑥﷯﷯﷮𝑑𝑥﷯ 𝑑𝑦﷮𝑑𝑥﷯=4𝑥+3 cos﷮𝑥﷯ We know that Slope of tangent × Slope of Normal =−1 4𝑥+3 cos﷮𝑥﷯﷯ × Slope of Normal =−1 Slope of Normal = −1﷮4𝑥 + 3 cos﷮𝑥﷯﷯ We need to find Slope of Normal at 𝑥=0 Slope of Normal at 𝑥=0﷯= − 1 ﷮4 0﷯+3 cos﷮0°﷯﷯= −1﷮0 + 3 1﷯﷯= −1﷮ 3﷯ Hence, Correct Answer is D

Chapter 6 Class 12 Application of Derivatives
Serial order wise

About the Author

Davneet Singh's photo - Teacher, Computer Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.