1. Chapter 6 Class 12 Application of Derivatives
  2. Serial order wise
  3. Ex 6.3

Ex 6.3,20 - Chapter 6 Class 12 Application of Derivatives

Last updated at May 29, 2018 by

Ex 6.3, 20 - Find equation of normal at (am2, am3) for ay2 = x3 - Finding equation of tangent/normal when point and curve is given

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  1. Chapter 6 Class 12 Application of Derivatives
  2. Serial order wise

    3. Ex 6.3

    Ex 6.4 →
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Transcript

Ex 6.3,20 Find the equation of the normal at the point ( 2 , 3 ) for the curve 2 = 3 We know that Slope of tangent is Given 2 = 3 Differentiating w.r.t. 2 = 3 2 = 3 . 2 =3 2 .2 =3 2 = 3 2 2 Slope of tangent at 2 , 3 is 2 , 3 = 3 2 2 2 3 = 3 2 4 2 2 3 = 3 2 We know that Slope of tangent Slope of Normal = 1 3 2 Slope of Normal = 1 Slope of Normal = 1 3 2 Slope of Normal = 2 3 Finding equation of normal Equation of Normal at 2 , 3 & having Slope 2 3 is 3 = 2 3 2 3 3 = 2 2 3 3 4 = 2 +2 2 2 +3 3 4 2 2 =0 2 +3 2 3 2 +2 =0 Required Equation of Normal is : + + =

Chapter 6 Class 12 Application of Derivatives
Serial order wise

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