Ex 6.3,17 - Chapter 6 Class 12 Application of Derivatives
Last updated at May 29, 2018 by Teachoo
Transcript
Ex 6.3,17 Find the points on the curve = 3 at which the slope of the tangent is equal to the y-coordinate of the point Let the Point be , on the Curve = 3 Where Slope of tangent at , = , i.e. , = Given = 3 Differentiating w.r.t. =3 2 Slope of tangent at , is , =3 2 From (1) , = 3 2 = Also Point , is on the Curve = 3 Point , must Satisfy the Equation of Curve i.e. = 3 Now our equations are 3 2 = (1) & = 3 (2) Putting Value of =3 2 in (3) 3 2 = 3 3 3 2 =0 2 3 =0 Hence the Required Point on the Curve are , & ,
Ex 6.3
Ex 6.3, 1
Ex 6.3,2
Ex 6.3,3
Ex 6.3,4
Ex 6.3, 5 Important
Ex 6.3,6
Ex 6.3,7
Ex 6.3,8
Ex 6.3,9 Important
Ex 6.3,10
Ex 6.3,11 Important
Ex 6.3,12
Ex 6.3,13
Ex 6.3,14 Important
Ex 6.3,15 Important
Ex 6.3,16
Ex 6.3,17 You are here
Ex 6.3,18 Important
Ex 6.3,19
Ex 6.3,20
Ex 6.3,21
Ex 6.3,22
Ex 6.3,23 Important
Ex 6.3,24 Important
Ex 6.3,25
Ex 6.3,26 Important
Ex 6.3,27
Chapter 6 Class 12 Application of Derivatives
Serial order wise
About the Author
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.