Ex 6.3,11 - Chapter 6 Class 12 Application of Derivatives
Last updated at May 29, 2018 by Teachoo
Transcript
Ex 6.3,11 Find the equation of all lines having slope 2 which are tangents to the curve 𝑦=1𝑥 − 3 , 𝑥≠3. The Equation of Given Curve is : 𝑦=1𝑥 − 3 We know that Slope of tangent is 𝑑𝑦𝑑𝑥 𝑑𝑦𝑑𝑥=𝑑1𝑥 − 3𝑑𝑥 𝑑𝑦𝑑𝑥=𝑑𝑑𝑥𝑥−3−1 𝑑𝑦𝑑𝑥=−1𝑥−3−1−1 . 𝑑𝑥 − 3𝑑𝑥 𝑑𝑦𝑑𝑥=−𝑥−3−2 𝑑𝑦𝑑𝑥=−1𝑥 − 32 But Given Slope of tangent =2 −1𝑥 − 32=2 −1=2𝑥−32 2𝑥−32=−1 𝑥−32=−1 2 We know that Square of any number is always positive So, 𝑥−32>0 ⇒ 𝑥−32=−1 2 not possible Thus , No tangent to the Curve has Slope 2
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Chapter 6 Class 12 Application of Derivatives
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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.