Check Full Chapter Explained - Continuity and Differentiability - Application of Derivatives (AOD) Class 12

Last updated at May 29, 2018 by Teachoo
Check Full Chapter Explained - Continuity and Differentiability - Application of Derivatives (AOD) Class 12
Transcript
Ex 6.3,4 Find the slope of the tangent to the curve 𝑦= 𝑥3−3𝑥+2 at the point whose 𝑥−coordinate is 3 𝑦= 𝑥3−3𝑥+2 We know that slope of tangent = 𝑑𝑦𝑑𝑥 𝑑𝑦𝑑𝑥=3 𝑥2−3 Since 𝑥−coordinate is 3 Putting 𝑥=3 in (1) 𝑑𝑦𝑑𝑥│𝑥 = 3=3 32−3 =3 ×9−3 =27−3 =24 Hence slope of tangent is 24
Ex 6.3
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Ex 6.3,4 You are here
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