Check Full Chapter Explained - Continuity and Differentiability - Application of Derivatives (AOD) Class 12
Ex 6.3,12 - Chapter 6 Class 12 Application of Derivatives
Last updated at Dec. 14, 2019 by Teachoo
Transcript
Ex 6.3,12 Find the equations of all lines having slope 0 which are tangent to the curve = 1 2 2 + 3 Given Curve is = 1 2 2 + 3 Slope of tangent is = 1 2 2 + 3 = 2 2 + 3 1 = 1 2 2 +3 2 . 2 2 + 3 = 2 2 +3 2 2 2 = 2 2 2 +3 2 1 = 2 1 2 2 + 3 2 Hence Slope of tangent is 2 1 2 2 + 3 2 Given Slope of tangent is 0 =0 2 1 2 2 + 3 2 =0 2 1 =0 2 2 + 3 2 2 1 =0 1 =0 =1 Finding y when =1 = 1 2 2 + 3 = 1 1 2 2 1 + 3 = 1 1 2 + 3 = 1 2 Point is , Thus , tangent passes through 1 , 1 2 Equation of tangent at 1 , 1 2 & having Slope zero is 1 2 =0 1 1 2 =0 = 1 2 Hence Equation of tangent is =
Ex 6.3
Ex 6.3, 1
Ex 6.3,2
Ex 6.3,3
Ex 6.3,4
Ex 6.3, 5 Important
Ex 6.3,6
Ex 6.3,7
Ex 6.3,8
Ex 6.3,9 Important
Ex 6.3,10
Ex 6.3,11 Important
Ex 6.3,12 You are here
Ex 6.3,13
Ex 6.3,14 Important
Ex 6.3,15 Important
Ex 6.3,16
Ex 6.3,17
Ex 6.3,18 Important
Ex 6.3,19
Ex 6.3,20
Ex 6.3,21
Ex 6.3,22
Ex 6.3,23 Important
Ex 6.3,24 Important
Ex 6.3,25
Ex 6.3,26 Important
Ex 6.3,27
Chapter 6 Class 12 Application of Derivatives
Serial order wise
About the Author
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.