Ex 6.3, 24 - Find equations of tangent and normal to hyperbola - Ex 6.3

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  1. Chapter 6 Class 12 Application of Derivatives
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Ex 6.3,24 Find the equations of the tangent and normal to the hyperbola 2 2 2 2 = 1 at the point ( 0 , 0) We know that Slope of tangent is 2 2 2 2 =1 2 2 =1 2 2 2 2 = 2 2 1 Differentiating w.r.t. 2 2 = 2 1 1 2 2 = 2 1 1 2 2 = 1 2 2 0 1 2 2 = 1 2 . 2 1 2 2 = 1 2 2 = 2 2 2 2 = 2 2 2 2 = 2 2 Slope of tangent at 0 , 0 is 0 , 0 = 2 0 2 0 We know that Slope of tangent Slope of Normal = 1 2 0 2 0 Slope of Normal = 1 Slope of Normal = 1 2 0 2 0 Slope of Normal = 2 0 2 0 Finding equation of tangent & normal

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.