Ex 6.3, 9 - Find point on y = x3 - 11x + 5 at which tangent - Ex 6.3

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  1. Chapter 6 Class 12 Application of Derivatives
  2. Serial order wise

Transcript

Ex 6.3,9 Find the point on the curve = 3 11 +5 at which the tangent is = 11. Equation of Curve is = 3 11 +5 We know that Slope of tangent is = 3 11 + 5 = 3 2 11 Also, Given tangent is = 12 Comparing with = + , when m is the Slope Slope of tangent =1 From (1) and (2) =1 3 2 11=1 3 2 =1+11 3 2 =12 2 = 12 3 2 =4 = 2 Hence , Points 2 , 9 & 2 , 19 But ( 2, 19) does not satisfy line y = x 11 As 19 2 11 Only point is (2, 9)

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.