Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class
Tangents and Normals (using Differentiation)
Question 2 Deleted for CBSE Board 2024 Exams
Question 3 Important Deleted for CBSE Board 2024 Exams
Question 4 Deleted for CBSE Board 2024 Exams
Question 5 Important Deleted for CBSE Board 2024 Exams
Question 6 Deleted for CBSE Board 2024 Exams
Question 7 Important Deleted for CBSE Board 2024 Exams
Question 8 Deleted for CBSE Board 2024 Exams
Question 9 Important Deleted for CBSE Board 2024 Exams
Question 10 Deleted for CBSE Board 2024 Exams
Question 11 Important Deleted for CBSE Board 2024 Exams
Question 12 Deleted for CBSE Board 2024 Exams
Question 13 Deleted for CBSE Board 2024 Exams
Question 14 (i) Deleted for CBSE Board 2024 Exams
Question 14 (ii) Important Deleted for CBSE Board 2024 Exams
Question 14 (iii) Deleted for CBSE Board 2024 Exams
Question 14 (iv) Important Deleted for CBSE Board 2024 Exams You are here
Question 14 (v) Deleted for CBSE Board 2024 Exams
Question 15 Important Deleted for CBSE Board 2024 Exams
Question 16 Deleted for CBSE Board 2024 Exams
Question 17 Deleted for CBSE Board 2024 Exams
Question 18 Important Deleted for CBSE Board 2024 Exams
Question 19 Deleted for CBSE Board 2024 Exams
Question 20 Deleted for CBSE Board 2024 Exams
Question 21 Important Deleted for CBSE Board 2024 Exams
Question 22 Deleted for CBSE Board 2024 Exams
Question 23 Important Deleted for CBSE Board 2024 Exams
Question 24 Important Deleted for CBSE Board 2024 Exams
Question 25 Deleted for CBSE Board 2024 Exams
Question 26 (MCQ) Important Deleted for CBSE Board 2024 Exams
Question 27 (MCQ) Deleted for CBSE Board 2024 Exams
Tangents and Normals (using Differentiation)
Last updated at May 29, 2023 by Teachoo
Question 14 Find the equations of the tangent and normal to the given curves at the indicated points: (iv) π¦=π₯2 ππ‘ (0, 0) Given Curve is π¦=π₯^2 Differentiating w.r.t.π₯ ππ¦/ππ₯=2π₯ We know that Slope of tangent is ππ¦/ππ₯ Given point is (0 , 0) Slope of tangent at (0 , 0) γππ¦/ππ₯βγ_((0 , 0) )=2(0) =0 We know that Slope of tangent Γ Slope if Normal =β1 0 Γ Slope if Normal =β1 Slope if Normal =(β1)/( 0) Equation of tangent at (0 , 0) & having Slope zero is (π¦β0)=0(π₯β0) We know that Equation of line at (π₯1 , π¦1)& having Slope m is π¦βπ¦1=π(π₯βπ₯1) Finding equation of tangent & normal Now Equation of line at (π₯1 , π¦1) & having Slope m is π¦βπ¦1=π(π₯βπ₯1) Equation of tangent at (0, 0) & Slope 0 is (π¦β0)=0(π₯β0) π¦β0=0 π=π Equation of Normal at (0, 0) & Slope (β1)/0 is (π¦β0)=1/0 (π₯β0) 0 Γ (π¦β0)=1(π₯β0) 0=π₯β0 π=π