Ex 6.3, 3 - Find slope of tangent y = x3 - x + 1 at x = 2 - Ex 6.3

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  1. Chapter 6 Class 12 Application of Derivatives
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Ex 6.3,3 Find the slope of the tangent to curve = 3 +1 at the point whose is 2. = 3 +1 We know that slope of tangent is = 3 + 1 =3 2 1+0 We need to find at the point whose is 2 Putting =2 in = 2 =3 2 2 1 =3 4 1 =12 1 =11 Hence slope of a tangent is 11

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