Question 3 - Tangents and Normals (using Differentiation) - Chapter 6 Class 12 Application of Derivatives
Last updated at April 16, 2024 by Teachoo
Tangents and Normals (using Differentiation)
Question 2 Deleted for CBSE Board 2024 Exams
Question 3 Important Deleted for CBSE Board 2024 Exams You are here
Question 4 Deleted for CBSE Board 2024 Exams
Question 5 Important Deleted for CBSE Board 2024 Exams
Question 6 Deleted for CBSE Board 2024 Exams
Question 7 Important Deleted for CBSE Board 2024 Exams
Question 8 Deleted for CBSE Board 2024 Exams
Question 9 Important Deleted for CBSE Board 2024 Exams
Question 10 Deleted for CBSE Board 2024 Exams
Question 11 Important Deleted for CBSE Board 2024 Exams
Question 12 Deleted for CBSE Board 2024 Exams
Question 13 Deleted for CBSE Board 2024 Exams
Question 14 (i) Deleted for CBSE Board 2024 Exams
Question 14 (ii) Important Deleted for CBSE Board 2024 Exams
Question 14 (iii) Deleted for CBSE Board 2024 Exams
Question 14 (iv) Important Deleted for CBSE Board 2024 Exams
Question 14 (v) Deleted for CBSE Board 2024 Exams
Question 15 Important Deleted for CBSE Board 2024 Exams
Question 16 Deleted for CBSE Board 2024 Exams
Question 17 Deleted for CBSE Board 2024 Exams
Question 18 Important Deleted for CBSE Board 2024 Exams
Question 19 Deleted for CBSE Board 2024 Exams
Question 20 Deleted for CBSE Board 2024 Exams
Question 21 Important Deleted for CBSE Board 2024 Exams
Question 22 Deleted for CBSE Board 2024 Exams
Question 23 Important Deleted for CBSE Board 2024 Exams
Question 24 Important Deleted for CBSE Board 2024 Exams
Question 25 Deleted for CBSE Board 2024 Exams
Question 26 (MCQ) Important Deleted for CBSE Board 2024 Exams
Question 27 (MCQ) Deleted for CBSE Board 2024 Exams
Tangents and Normals (using Differentiation)
Last updated at April 16, 2024 by Teachoo
Question 3 Find the slope of the tangent to curve 𝑦=𝑥^3−𝑥+1 at the point whose 𝑥−𝑐𝑜𝑜𝑟𝑑𝑖𝑛𝑎𝑡𝑒 is 2. 𝑦=𝑥^3−𝑥+1 We know that slope of tangent is 𝑑𝑦/𝑑𝑥 𝑑𝑦/𝑑𝑥=𝑑(𝑥^3 − 𝑥 + 1)/𝑑𝑥 𝑑𝑦/𝑑𝑥=3𝑥^2−1+0 We need to find 𝑑𝑦/𝑑𝑥 at the point whose 𝑥−𝑐𝑜𝑜𝑟𝑑𝑖𝑛𝑎𝑡𝑒 is 2 Putting 𝑥=2 in 𝑑𝑦/𝑑𝑥 〖𝑑𝑦/𝑑𝑥│〗_(𝑥 = 2)=3(2)^2−1 =3 ×4−1 =12−1 =11 Hence slope of a tangent is 11