Ex 6.3,10 - Chapter 6 Class 12 Application of Derivatives

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Ex 6.3,10 Find the equation of all lines having slope 1 that are tangents to the curve = 1 1 , 1. Equation of Curve is = 1 1 We know that Slope of tangent is = 1 1 = 1 1 1 1 1 2 = 0 1 1 0 1 1 2 = 1 1 2 So, Slope of tangent is 1 1 2 But ,Given Slope of tangent = 1 1 1 2 = 1 1 1 2 =1 1= 1 2 1 2 =1 1= 1 1= 1 Hence =2 , 0 Equation of 1st tangent at 2 , 1 & having Slope 1 is 1 = 1 2 1= +2 + =2+1 + = Equation of 2nd tangent 0 , 1 & having Slope 1 is 1 = 1 0 +1= +0 + + = Hence the Required Equation of lines are + 3=0 & + +1=0