Ex 3.3, 20 - Prove sin x - sin 3x / sin2 x - cos2 x = 2 sin x - cos x + cos y formula

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Ex 3.3, 20 - Chapter 3 Class 11 Trigonometric Functions - Part 2

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  1. Chapter 3 Class 11 Trigonometric Functions (Term 2)
  2. Serial order wise

Transcript

Ex 3.3, 20 Prove that 〖sin x − 〗⁡sin⁡3x /(sin2⁡x − cos2⁡x ) = 2 sin x Taking L.H.S. 〖sin x −〗⁡sin⁡3x /(sin2⁡x − cos2⁡x ) We solve sin x – sin 3x & sin2 x – cos2 x separately Now, sin⁡〖𝑥 − sin⁡3𝑥 〗/sin2⁡〖𝑥 − cos2⁡𝑥 〗 = 〖2 𝑐𝑜𝑠 〗⁡〖2𝑥 〖 sin〗⁡〖(−𝑥)〗 〗/〖−𝑐𝑜𝑠〗⁡2𝑥 = 〖2 𝑐𝑜𝑠〗⁡〖2𝑥 〖(− sin〗⁡𝑥)〗/〖−𝑐𝑜𝑠〗⁡2𝑥 = 2sin x = R.H.S. Hence L.H.S. = R.H.S. Hence proved

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.