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Ex 3.3, 20 - Prove sin x - sin 3x / sin2 x - cos2 x = 2 sin x - cos x + cos y formula

Ex 3.3, 20 - Chapter 3 Class 11 Trigonometric Functions - Part 2


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Ex 3.3, 20 Prove that 〖sin x − 〗⁡sin⁡3x /(sin2⁡x − cos2⁡x ) = 2 sin x Taking L.H.S. 〖sin x −〗⁡sin⁡3x /(sin2⁡x − cos2⁡x ) We solve sin x – sin 3x & sin2 x – cos2 x separately Now, sin⁡〖𝑥 − sin⁡3𝑥 〗/sin2⁡〖𝑥 − cos2⁡𝑥 〗 = 〖2 𝑐𝑜𝑠 〗⁡〖2𝑥 〖 sin〗⁡〖(−𝑥)〗 〗/〖−𝑐𝑜𝑠〗⁡2𝑥 = 〖2 𝑐𝑜𝑠〗⁡〖2𝑥 〖(− sin〗⁡𝑥)〗/〖−𝑐𝑜𝑠〗⁡2𝑥 = 2sin x = R.H.S. Hence L.H.S. = R.H.S. Hence proved

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.