Ex 3.3, 16 - Class 11
Last updated at Dec. 8, 2016 by Teachoo
Transcript
Ex 3.3, 16 Prove that πππ β‘γ9π₯ βγ πππ γβ‘5π₯ γ/(π ππ 17π₯ β π ππβ‘3π₯ ) =βπ ππβ‘γ2π₯ γ/πππ β‘10π₯ Taking L.H.S πππ β‘γ9π₯ βγ πππ γβ‘5π₯ γ/(π ππ 17π₯ β π ππβ‘3π₯ ) We solve cos 9x β cos 5x & sin 17x β sin 3x seperately Now, πππ β‘γ9π₯ βγ πππ γβ‘5π₯ γ/(π ππ 17π₯ β π ππβ‘3π₯ ) = (β2 γsin γβ‘γ(7x)γsin γβ‘γ(2x)γ γ)/(2 πππ β‘γ(10x)sinβ‘γ (7x)γ γ ) = γβsinγβ‘γ(2x)γ/πππ β‘γ(10x)γ = R.H.S So, L.H.S. = R.H.S. Hence proved
Ex 3.3
Ex 3.3, 1
Ex 3.3, 2
Ex 3.3, 3
Ex 3.3, 4 Important
Ex 3.3, 5 Important
Ex 3.3, 6
Ex 3.3, 7
Ex 3.3, 8 Important
Ex 3.3, 9
Ex 3.3, 10
Ex 3.3, 11 Important
Ex 3.3, 12
Ex 3.3, 13
Ex 3.3, 14
Ex 3.3, 15
Ex 3.3, 16 You are here
Ex 3.3, 17
Ex 3.3, 18 Important
Ex 3.3, 19
Ex 3.3, 20
Ex 3.3, 21 Important
Ex 3.3, 22
Ex 3.3, 23 Important
Ex 3.3, 24
Ex 3.3, 25
Chapter 3 Class 11 Trigonometric Functions
Serial order wise
About the Author
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.