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Ex 3.3, 14 - Chapter 3 Class 11 Trigonometric Functions
Last updated at Dec. 8, 2016 by Teachoo
Transcript
Ex 3.3, 14 Prove that sin 2x + 2sin 4x + sin 6x = 4cos2 x sin 4x Taking L.H.S. sin 2x + 2sin 4x + sin 6x = (sin 6x + sin 2x) + 2sin 4x = 2 sin ((6 + 2 )/2) cos ((6 2 )/2) + 2sin 4x = 2 sin (8 /2) cos (4 /2) + 2sin 4x = 2 sin 4x cos 2x + 2sin 4x = 2 sin 4x (cos 2x + 1) = 2 sin 4x ( 2cos2x 1 + 1) = 2 sin 4x (2cos2x) = 4 sin 4x cos2x = R.H.S Hence L.H.S = R.H.S Hence proved
Ex 3.3
Ex 3.3, 1
Ex 3.3, 2 Important
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Ex 3.3, 11 Important
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Ex 3.3, 14 You are here
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Ex 3.3, 18 Important
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Chapter 3 Class 11 Trigonometric Functions
Serial order wise
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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.