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Ex 3.3, 1 Prove that sin2 π/6 + cos2 π/3 – tan2 π/4 = – 1/2 Solving L.H.S sin2 π/6 + cos2 π/3 − tan2 π/4 Putting π = 180° = sin2 (180° )/6 + cos2 (180° )/3 – tan2 (180° )/4 = sin2 30° + cos2 60° – tan2 45° Putting sin 30° = 1/2 , sin 60° = 1/2 , tan 45° = 1 Ex 3.3, 1 Prove that sin2 π/6 + cos2 π/3 – tan2 π/4 = – 1/2 Solving L.H.S sin2 π/6 + cos2 π/3 − tan2 π/4 Putting π = 180° = sin2 (180° )/6 + cos2 (180° )/3 – tan2 (180° )/4 = sin2 30° + cos2 60° – tan2 45° Putting sin 30° = 1/2 , sin 60° = 1/2 , tan 45° = 1 = (𝟏/𝟐)^𝟐 + (𝟏/𝟐)^𝟐 – 12 = 1/4+ 1/4 −1 = (1 + 1 − 4 )/4 = (−2)/4 = (−𝟏)/𝟐 = R.H.S. Hence proved

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.