Ex 3.3, 5 (i) - Chapter 3 Class 11 Trigonometric Functions (Term 2)
Last updated at Aug. 27, 2021 by Teachoo
Transcript
Ex 3.3, 5 Find the value of: sin 75° sin 75° = sin (45° + 30°) = sin 45° cos 30° + cos 45° sin 30° = 1/√2 × √3/2 + 1/√2 × 1/2 = 1/√2 (√3/2 " + " 1/2) = (√𝟑 + 𝟏)/(𝟐√𝟐) sin (x + y) = sin x cos y + cos x sin y Putting x = 45° and y = 30°
Ex 3.3
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Ex 3.3, 5 (i) Important You are here
Ex 3.3, 5 (ii)
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Chapter 3 Class 11 Trigonometric Functions (Term 2)
Serial order wise
- Ex 3.1
- Ex 3.2
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Ex 3.3
- Ex 3.4
- Examples
- Miscellaneous
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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.