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Ex 3.3, 12 - Prove that sin2 6x - sin2 4x = sin⁡2x sin⁡10x - (x + y) formula

Ex 3.3, 12 - Chapter 3 Class 11 Trigonometric Functions - Part 2

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Ex 3.3, 12 Prove that sin2 6 sin2 4 = sin 2 sin 10 Solving L.H.S. sin2 6x sin2 4x Using a2 b2 = (a + b) (a - b) = (sin 6x + sin 4x) (sin 6x sin 4x) Lets calculate (sin 6x + sin 4x) and (sin 6x sin 4x) separately Hence sin2 6x sin2 4x = (sin 6x + sin 4x) (sin 6x sin 4x) = (2 sin 5x cos x) (2 cos 5x sin x) = (2 sin 5x cos 5x) . (2 sin x cos x) = (sin 10x) (sin 2x) = R.H.S. Hence, L.H.S. = R.H.S. Hence proved

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.