Last updated at May 6, 2021 by

Transcript

Example 27 (Supplementary NCERT) Show that the vectors π β = π Μ β 2π Μ + 3π Μ, π β = β2π Μ + 3π Μ β 4π Μ and π β = π Μ β 3π Μ + 5π Μ are coplanarThree vectors π β, π β, π β are coplanar if [π β" " π β" " π β ] = 0 Given, π β = π Μ β 2π Μ + 3π Μ π β = β2π Μ + 3π Μ β 4π Μ π β = π Μ β 3π Μ + Ξ»π Μ [π β" " π β" " π β ] = |β 8(1&β2&3@β2&3&β4@1&β3&5)| = 1[(3Γ5)β(β3Γβ4) ] β (β2) [(β2Γ5)β(1Γβ4) ] + 3[(β2Γβ3)β(1Γ3) ] = 1 [15β(3 Γ4)]+2[β10β(β4)]+3[(2 Γ3)β3] = 1 [15β12]+2[β10+4]+3[6β3] = 1 [3]+2[β6]+3[3] = 3 β 12 + 9 = 0 Since [π β" " π β" " π β ] = 0 Vectors π β, π β, π β are coplanar

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Example 26 (Supplementary NCERT) Deleted for CBSE Board 2022 Exams

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Example 28 (Supplementary NCERT) Important Deleted for CBSE Board 2022 Exams

Example 29 (Supplementary NCERT) Important Deleted for CBSE Board 2022 Exams

Example 30 (Supplementary NCERT) Important Deleted for CBSE Board 2022 Exams

Example 31 (Supplementary NCERT) Important Deleted for CBSE Board 2022 Exams

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.