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Example 26 (Supplementary NCERT) Deleted for CBSE Board 2023 Exams

Example 27 (Supplementary NCERT) Deleted for CBSE Board 2023 Exams You are here

Example 28 (Supplementary NCERT) Important Deleted for CBSE Board 2023 Exams

Example 29 (Supplementary NCERT) Important Deleted for CBSE Board 2023 Exams

Example 30 (Supplementary NCERT) Important Deleted for CBSE Board 2023 Exams

Example 31 (Supplementary NCERT) Important Deleted for CBSE Board 2023 Exams

Last updated at March 23, 2023 by Teachoo

Example 27 (Supplementary NCERT) Show that the vectors π β = π Μ β 2π Μ + 3π Μ, π β = β2π Μ + 3π Μ β 4π Μ and π β = π Μ β 3π Μ + 5π Μ are coplanarThree vectors π β, π β, π β are coplanar if [π β" " π β" " π β ] = 0 Given, π β = π Μ β 2π Μ + 3π Μ π β = β2π Μ + 3π Μ β 4π Μ π β = π Μ β 3π Μ + Ξ»π Μ [π β" " π β" " π β ] = |β 8(1&β2&[email protected]β2&3&β[email protected]&β3&5)| = 1[(3Γ5)β(β3Γβ4) ] β (β2) [(β2Γ5)β(1Γβ4) ] + 3[(β2Γβ3)β(1Γ3) ] = 1 [15β(3 Γ4)]+2[β10β(β4)]+3[(2 Γ3)β3] = 1 [15β12]+2[β10+4]+3[6β3] = 1 [3]+2[β6]+3[3] = 3 β 12 + 9 = 0 Since [π β" " π β" " π β ] = 0 Vectors π β, π β, π β are coplanar