Example 8 - Find unit vector in direction of sum of vectors

Example 8 - Chapter 10 Class 12 Vector Algebra - Part 2

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Example 8 Find the unit vector in the direction of the sum of the vectors, š‘Ž āƒ— = 2š‘– Ģ‚ + 2 š‘— Ģ‚ – 5š‘˜ Ģ‚ and š‘ āƒ— = 2š‘– Ģ‚ + š‘— Ģ‚ + 3š‘˜ Ģ‚ Given š’‚ āƒ— = 2š‘– Ģ‚ + 2š‘— Ģ‚ – 5š‘˜ Ģ‚ š’ƒ āƒ— = 2š‘– Ģ‚ + 1š‘— Ģ‚ + 3š‘˜ Ģ‚ Let š’„ āƒ— = (š’‚ āƒ— + š’ƒ āƒ—) = (2 + 2) š‘– Ģ‚ + (2 + 1) š‘— Ģ‚ + (–5 + 3) š‘˜ Ģ‚ = 4š‘– Ģ‚ + 3š‘— Ģ‚ – 2š‘˜ Ģ‚ ∓ š’„ āƒ— = 4š’Š Ģ‚ + 3š’‹ Ģ‚ – 2š’Œ Ģ‚ Magnitude of š‘ āƒ— = √(42+32+(āˆ’2)2) |š’„ āƒ— | = √(16+9+4) = āˆššŸšŸ— Unit vector in direction of š‘ āƒ— = šŸ/|š’„ āƒ— | š’„ āƒ— š‘ Ģ‚ = 1/√29 ["4" š‘– Ģ‚" + 3" š‘— Ģ‚" āˆ’ 2" š‘˜ Ģ‚ ] š‘ Ģ‚ = 4/√29 š‘– Ģ‚" " + 3/√29 š‘— Ģ‚" "– 2/√29 š‘˜ Ģ‚" " Thus, Required unit vector = šŸ’/āˆššŸšŸ— š’Š Ģ‚" " + šŸ‘/āˆššŸšŸ— š’‹ Ģ‚" "– šŸ/āˆššŸšŸ— š’Œ Ģ‚

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