Example 22 - Find |a x b|, if a=2i+j+3k and b=3i+5j-2k - Examples

Example 22 - Chapter 10 Class 12 Vector Algebra - Part 2

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Example 22 Find |š‘Ž āƒ— Ɨ š‘ āƒ—|, if š‘Ž āƒ— = 2š‘– Ģ‚ + š‘— Ģ‚ + 3š‘˜ Ģ‚ and š‘ āƒ— = 3š‘– Ģ‚ + 5š‘— Ģ‚ āˆ’ 2š‘˜ Ģ‚ Given š’‚ āƒ— = 2š‘– Ģ‚ + š‘— Ģ‚ + 3š‘˜ Ģ‚ š’ƒ āƒ— = 3š‘– Ģ‚ + 5š‘— Ģ‚ āˆ’ 2š‘˜ Ģ‚ Now, š’‚ āƒ— Ɨ š’ƒ āƒ— = |ā– 8(š‘– Ģ‚&š‘— Ģ‚&š‘˜ Ģ‚@2&1&3@3&5&āˆ’2)| = š‘– Ģ‚ (1 Ɨ (-2) – 5 Ɨ 3) āˆ’ š‘— Ģ‚ (2 Ɨ (-2) āˆ’ 3 Ɨ 3) + š‘˜ Ģ‚ (2 Ɨ 5 āˆ’ 3 Ɨ 1) = š‘– Ģ‚ (āˆ’2 āˆ’15) āˆ’ š‘— Ģ‚ (āˆ’4 āˆ’9) + š‘˜ Ģ‚ (10 āˆ’ 3) = –17š’Š Ģ‚ + 13š’‹ Ģ‚ + 7š’Œ Ģ‚ So, Magnitude of š‘Ž āƒ— Ɨ š‘ āƒ— = √((āˆ’17)2+(13)2+(7)2) |š‘Ž āƒ—" Ɨ " š‘ āƒ— | = √(289+169+49) = √507 Thus, |š‘Ž āƒ—" Ɨ " š‘ āƒ— | = āˆššŸ“šŸŽšŸ•

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