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Example 16 - Chapter 10 Class 12 Vector Algebra (Term 2)
Last updated at March 22, 2023 by Teachoo
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Transcript
Example 16 Find the projection of the vector π β = 2π Μ + 3π Μ + 2π Μ on the vector π β = π Μ + 2π Μ + π Μ. Given π β = 2π Μ + 3π Μ + 2π Μ π β = 1π Μ + 2π Μ + 1π Μ We know that Projection of vector π β on π β = π/("|" π β"|" ) (π β. π β) Finding π β. π β (π β. π β) = (2 Γ 1) + (3 Γ 2) + (2 Γ 1) = 2 + 6 + 2 = 10 Magnitude of π β = β(12+22+12) |π β | = β(1+4+1) = βπ Now, Projection of vector π β on π β = 1/("|" π β"|" ) (π β. π β) = 1/β6 (10) = 10/β6 = 10/β6 Γ β6/β6 = 10/6 Γ β6 = π/π βπ
