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Example 26 (Supplementary NCERT) - Chapter 10 Class 12 Vector Algebra (Term 2)
Last updated at March 16, 2023 by Teachoo
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Transcript
Example 26 (Supplementary NCERT) Find π β.(π β Γ π β), if π β = 2π Μ + π Μ + 3π Μ , π β = βπ Μ + 2π Μ + π Μ , π β = 3π Μ + π Μ + 2π ΜGiven, π β = 2π Μ + π Μ + 3π Μ , π β = βπ Μ + 2π Μ + π Μ , π β = 3π Μ + π Μ + 2π Μ π β.(π β Γ π β) = [π β" " π β" " π β ] = |β 8(π&π&π@βπ&π&π@π&π&π)| = 2[(2Γ2)β(1Γ1) ] β 1[(β1Γ2)β(3Γ1) ] + 3[(β1Γ1)β(3Γ2)] = 2 [4β1]β1(β2β3)+3[β1β6] = 2(3) β 1(β5) + 3(β7) = 6 + 5 β 21 = 11 β 21 = β 10 β΄ π β.(π β Γ π β) = β10
