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Example 26 (Supplementary NCERT) - Chapter 10 Class 12 Vector Algebra
Last updated at Dec. 19, 2018 by Teachoo
Transcript
Given, ๐ โ = 2๐ ฬ + ๐ ฬ + 3๐ ฬ , ๐ โ = โ๐ ฬ + 2๐ ฬ + ๐ ฬ , ๐ โ = 3๐ ฬ + ๐ ฬ + 2๐ ฬ ๐ โ.(๐ โ ร ๐ โ) = [๐ โ" " ๐ โ" " ๐ โ ] = |โ 8(2&1&3@โ1&2&1@3&1&2)| = 2[(2ร2)โ(1ร1) ] โ 1[(โ1ร2)โ(3ร1) ] + 3[(โ1ร1)โ(3ร2)] = 2 [4โ1]โ1(โ2โ3)+3[โ1โ6] = 2(3) โ 1(โ5) + 3(โ7) = 6 + 5 โ 21 = 11 โ 21 = โ 10 โด ๐ โ.(๐ โ ร ๐ โ) = โ10
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Example 26 (Supplementary NCERT) You are here
Example 27 (Supplementary NCERT)
Example 28 (Supplementary NCERT) Important
Example 29 (Supplementary NCERT) Important
Example 30 (Supplementary NCERT) Important
Example 31 (Supplementary NCERT) Important
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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.