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Example 26 (Supplementary NCERT) Deleted for CBSE Board 2022 Exams You are here

Example 27 (Supplementary NCERT) Deleted for CBSE Board 2022 Exams

Example 28 (Supplementary NCERT) Important Deleted for CBSE Board 2022 Exams

Example 29 (Supplementary NCERT) Important Deleted for CBSE Board 2022 Exams

Example 30 (Supplementary NCERT) Important Deleted for CBSE Board 2022 Exams

Example 31 (Supplementary NCERT) Important Deleted for CBSE Board 2022 Exams

Last updated at May 6, 2021 by Teachoo

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Hello! Teachoo has made these pages with hours (even days!) of effort and love. Your Board exams are coming, if Teachoo has been of any help in the whole year of studying... please consider making a donation to support us.

Example 26 (Supplementary NCERT) Find π β.(π β Γ π β), if π β = 2π Μ + π Μ + 3π Μ , π β = βπ Μ + 2π Μ + π Μ , π β = 3π Μ + π Μ + 2π ΜGiven, π β = 2π Μ + π Μ + 3π Μ , π β = βπ Μ + 2π Μ + π Μ , π β = 3π Μ + π Μ + 2π Μ π β.(π β Γ π β) = [π β" " π β" " π β ] = |β 8(π&π&π@βπ&π&π@π&π&π)| = 2[(2Γ2)β(1Γ1) ] β 1[(β1Γ2)β(3Γ1) ] + 3[(β1Γ1)β(3Γ2)] = 2 [4β1]β1(β2β3)+3[β1β6] = 2(3) β 1(β5) + 3(β7) = 6 + 5 β 21 = 11 β 21 = β 10 β΄ π β.(π β Γ π β) = β10