Example 26 (Supplementary NCERT).jpg

  1. Chapter 10 Class 12 Vector Algebra
  2. Serial order wise

Transcript

Given, ๐‘Ž โƒ— = 2๐‘– ฬ‚ + ๐‘— ฬ‚ + 3๐‘˜ ฬ‚ , ๐‘ โƒ— = โ€“๐‘– ฬ‚ + 2๐‘— ฬ‚ + ๐‘˜ ฬ‚ , ๐‘ โƒ— = 3๐‘– ฬ‚ + ๐‘— ฬ‚ + 2๐‘˜ ฬ‚ ๐‘Ž โƒ—.(๐‘ โƒ— ร— ๐‘ โƒ—) = [๐‘Ž โƒ—" " ๐‘ โƒ—" " ๐‘ โƒ— ] = |โ– 8(2&1&3@โˆ’1&2&1@3&1&2)| = 2[(2ร—2)โˆ’(1ร—1) ] โˆ’ 1[(โˆ’1ร—2)โˆ’(3ร—1) ] + 3[(โˆ’1ร—1)โˆ’(3ร—2)] = 2 [4โˆ’1]โˆ’1(โˆ’2โˆ’3)+3[โˆ’1โˆ’6] = 2(3) โ€“ 1(โ€“5) + 3(โ€“7) = 6 + 5 โ€“ 21 = 11 โ€“ 21 = โ€“ 10 โˆด ๐‘Ž โƒ—.(๐‘ โƒ— ร— ๐‘ โƒ—) = โ€“10

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.