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Example 26 (Supplementary NCERT) - Chapter 10 Class 12 Vector Algebra
Last updated at Dec. 19, 2018 by Teachoo
Transcript
Given, ๐ โ = 2๐ ฬ + ๐ ฬ + 3๐ ฬ , ๐ โ = โ๐ ฬ + 2๐ ฬ + ๐ ฬ , ๐ โ = 3๐ ฬ + ๐ ฬ + 2๐ ฬ ๐ โ.(๐ โ ร ๐ โ) = [๐ โ" " ๐ โ" " ๐ โ ] = |โ 8(2&1&3@โ1&2&1@3&1&2)| = 2[(2ร2)โ(1ร1) ] โ 1[(โ1ร2)โ(3ร1) ] + 3[(โ1ร1)โ(3ร2)] = 2 [4โ1]โ1(โ2โ3)+3[โ1โ6] = 2(3) โ 1(โ5) + 3(โ7) = 6 + 5 โ 21 = 11 โ 21 = โ 10 โด ๐ โ.(๐ โ ร ๐ โ) = โ10
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Example 26 (Supplementary NCERT) Not in Syllabus - CBSE Exams 2021 You are here
Example 27 (Supplementary NCERT) Not in Syllabus - CBSE Exams 2021
Example 28 (Supplementary NCERT) Important Not in Syllabus - CBSE Exams 2021
Example 29 (Supplementary NCERT) Important Not in Syllabus - CBSE Exams 2021
Example 30 (Supplementary NCERT) Important Not in Syllabus - CBSE Exams 2021
Example 31 (Supplementary NCERT) Important Not in Syllabus - CBSE Exams 2021
About the Author
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.