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Example 26 (Supplementary NCERT) Deleted for CBSE Board 2022 Exams

Example 27 (Supplementary NCERT) Deleted for CBSE Board 2022 Exams

Example 28 (Supplementary NCERT) Important Deleted for CBSE Board 2022 Exams

Example 29 (Supplementary NCERT) Important Deleted for CBSE Board 2022 Exams

Example 30 (Supplementary NCERT) Important Deleted for CBSE Board 2022 Exams

Example 31 (Supplementary NCERT) Important Deleted for CBSE Board 2022 Exams

Last updated at May 6, 2021 by Teachoo

Example 7 Find a vector in the direction of vector π β = π Μ β 2π Μ that has magnitude 7 units. Given π β = π Μ β 2π Μ = 1π Μ β 2π Μ + 0π Μ Magnitude of π β = β(12+(β2)2+02) |π β | = β(1+4+0) = βπ Unit vector in direction of π β = π/(π΄πππππππ π ππ π β ) Γ π β π Μ = 1/β5 ["1" π Μ" + " 2π Μ" + " 0π Μ ] π Μ = 1/β5 π Μ β 2/β5 π Μ Thus, Vector having a magnitude 1 = 1/β5 π Μ β 2/β5 π Μ Vector having a magnitude 7 = 7[1/β5 " " π Μ" β " 2/β5 " " π Μ" " ] = 7/β5 " " π Μ" β " 14/β5 " " π Μ Thus, required vector is π/βπ " " π Μ" β " ππ/βπ " " π Μ