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Example 7 - Chapter 10 Class 12 Vector Algebra (Term 2)
Last updated at March 22, 2023 by Teachoo
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Transcript
Example 7 Find a vector in the direction of vector π β = π Μ β 2π Μ that has magnitude 7 units. Given π β = π Μ β 2π Μ = 1π Μ β 2π Μ + 0π Μ Magnitude of π β = β(12+(β2)2+02) |π β | = β(1+4+0) = βπ Unit vector in direction of π β = π/(π΄πππππππ π ππ π β ) Γ π β π Μ = 1/β5 ["1" π Μ" + " 2π Μ" + " 0π Μ ] π Μ = 1/β5 π Μ β 2/β5 π Μ Thus, Vector having a magnitude 1 = 1/β5 π Μ β 2/β5 π Μ Vector having a magnitude 7 = 7[1/β5 " " π Μ" β " 2/β5 " " π Μ" " ] = 7/β5 " " π Μ" β " 14/β5 " " π Μ Thus, required vector is π/βπ " " π Μ" β " ππ/βπ " " π Μ
