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Example 17 - Chapter 10 Class 12 Vector Algebra (Term 2)
Last updated at March 16, 2023 by Teachoo
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Transcript
Example 17 Find |π β β π β| , if two vectors a and b are such that |π β| = 2, |π β| = 3 and π β β π β = 4. Given, |π β | = 2 , |π β | = 2 & π β. π β = 4 We need to find |π ββπ β | Taking square, |π ββπ β |2 = (π ββπ β). (π ββπ β) = π β . π β β π β . π β β π β. π β + π β . π β = π β . π β β π β . π β β π β . π β + π β . π β = π β. π β β 2π β . π β + π β. π β = |π β |2 β 2π β. π β + |π β |2 = 22 β 2 Γ 4 + 32 = 4 β 8 + 9 = 5 Thus, |π ββπ β |2 = 5 |π ββπ β | = Β± β5 Since magnitude is not negative, So, |π ββπ β | = βπ
