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Example 26 (Supplementary NCERT) Deleted for CBSE Board 2022 Exams

Example 27 (Supplementary NCERT) Deleted for CBSE Board 2022 Exams

Example 28 (Supplementary NCERT) Important Deleted for CBSE Board 2022 Exams

Example 29 (Supplementary NCERT) Important Deleted for CBSE Board 2022 Exams

Example 30 (Supplementary NCERT) Important Deleted for CBSE Board 2022 Exams

Example 31 (Supplementary NCERT) Important Deleted for CBSE Board 2022 Exams

Last updated at May 6, 2021 by Teachoo

Example 17 Find |π β β π β| , if two vectors a and b are such that |π β| = 2, |π β| = 3 and π β β π β = 4. Given, |π β | = 2 , |π β | = 2 & π β. π β = 4 We need to find |π ββπ β | Taking square, |π ββπ β |2 = (π ββπ β). (π ββπ β) = π β . π β β π β . π β β π β. π β + π β . π β = π β . π β β π β . π β β π β . π β + π β . π β = π β. π β β 2π β . π β + π β. π β = |π β |2 β 2π β. π β + |π β |2 = 22 β 2 Γ 4 + 32 = 4 β 8 + 9 = 5 Thus, |π ββπ β |2 = 5 |π ββπ β | = Β± β5 Since magnitude is not negative, So, |π ββπ β | = βπ