Slide11.JPG

  1. Chapter 10 Class 12 Vector Algebra
  2. Serial order wise
Ask Download

Transcript

Ex 10.5, 1 (Supplementary NCERT) Find [π‘ŽΒ βƒ—" " 𝑏 ⃗" " 𝑐 ⃗ ] if π‘ŽΒ βƒ— = 𝑖 ̂ – 2𝑗 ̂ + 3π‘˜Β Μ‚ , 𝑏 ⃗ = 2𝑖 ̂ – 3𝑗 ̂ + π‘˜Β Μ‚ , 𝑐 ⃗ = 3𝑖 ̂ + 𝑗 ̂ – 2π‘˜Β Μ‚Given, π‘ŽΒ βƒ— = 𝑖 ̂ – 2𝑗 ̂ + 3π‘˜Β Μ‚ , 𝑏 ⃗ = 2𝑖 ̂ – 3𝑗 ̂ + π‘˜Β Μ‚ , 𝑐 ⃗ = 3𝑖 ̂ + 𝑗 ̂ – 2π‘˜Β Μ‚ π‘ŽΒ βƒ—.(𝑏 ⃗ Γ— 𝑐 ⃗) = [π‘ŽΒ βƒ—" " 𝑏 ⃗" " 𝑐 ⃗ ] = |β– 8(1&βˆ’2&3@2&βˆ’3&1@3&1&βˆ’2)| = 1[(βˆ’3Γ—βˆ’2)βˆ’(1Γ—1) ] βˆ’ (–2)[(2Γ—βˆ’2)βˆ’(3Γ—1) ] + 3[(2Γ—1)βˆ’(3Γ—βˆ’3)] = 1 [6βˆ’1]+2(βˆ’4βˆ’3)+3[2+9] = 1(5) + 2(–7) + 3(11) = 5 – 14 + 33 = 38 – 14 = 24 ∴ [π‘ŽΒ βƒ—" " 𝑏 ⃗" " 𝑐 ⃗ ] = 24

About the Author

Davneet Singh's photo - Teacher, Computer Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 7 years. He provides courses for Mathematics and Science from Class 6 to 12. You can learn personally from here https://www.teachoo.com/premium/maths-and-science-classes/.
Jail