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1. Chapter 10 Class 12 Vector Algebra
2. Serial order wise
3. Ex 10.5 (Supplementary NCERT)

Transcript

Ex 10.5, 4 (Supplementary NCERT) Let 𝑎 ⃗ = 𝑖 ̂ + 𝑗 ̂ + 𝑘 ̂, 𝑏 ⃗ = 𝑖 ̂ and 𝑐 ⃗ = c1𝑖 ̂ + c2𝑗 ̂ + c3𝑘 ̂ are coplanar (a) If c1 = 1 and c2 = 2, find c3 which makes 𝑎 ⃗, 𝑏 ⃗, 𝑐 ⃗ coplanar Given c1 = 1 and c2 = 2 So, 𝑎 ⃗ = 𝑖 ̂ + 𝑗 ̂ + 𝑘 ̂ 𝑏 ⃗ = 𝑖 ̂ = 𝑖 ̂ + 0𝑗 ̂ + 0𝑘 ̂ 𝑐 ⃗ = c1𝑖 ̂ + c2𝑗 ̂ + c3𝑘 ̂ = 1𝑖 ̂ + 2𝑗 ̂ + c3𝑘 ̂ Three vectors 𝑎 ⃗, 𝑏 ⃗, 𝑐 ⃗ are coplanar if [𝒂 ⃗" " 𝒃 ⃗" " 𝒄 ⃗ ] = 0 Finding [𝒂 ⃗" " 𝒃 ⃗" " 𝒄 ⃗ ] [𝑎 ⃗" " 𝑏 ⃗" " 𝑐 ⃗ ] = |■8(1&1&1@1&0&0@1&2&𝑐_3 )| 0 = 1[(0 × 𝑐_3 )−(0 × 2) ] − 1[(1 × 𝑐_3 )−(1 × 0) ] + 1[(1 × 2)−(1 × 0)] 0 = 1 [0−0]−1[𝑐_3−0]+1[2−0] 0 = 0 – 𝑐_3 + 2 0 = – 𝑐_3 + 2 𝒄_𝟑 = 2 Therefore, 𝑎 ⃗,𝑏,𝑐 ⃗ are coplanar if 𝑐_3 = 2 Ex 10.5, 4 (Supplementary NCERT) Let 𝑎 ⃗ = 𝑖 ̂ + 𝑗 ̂ + 𝑘 ̂, 𝑏 ⃗ = 𝑖 ̂ and 𝑐 ⃗ = c1𝑖 ̂ + c2𝑗 ̂ + c3𝑘 ̂ are coplanar (b) If c2 = –1 and c3 = 1, show that no value of c1 can make 𝑎 ⃗, 𝑏 ⃗, 𝑐 ⃗ coplanar Given c2 = –1 and c3 = 1 So, 𝑎 ⃗ = 𝑖 ̂ + 𝑗 ̂ + 𝑘 ̂ 𝑏 ⃗ = 𝑖 ̂ = 𝑖 ̂ + 0𝑗 ̂ + 0𝑘 ̂ 𝑐 ⃗ = c1𝑖 ̂ + c2𝑗 ̂ + c3𝑘 ̂ = c1𝑖 ̂ – 1𝑗 ̂ + 1𝑘 ̂ Three vectors 𝑎 ⃗, 𝑏 ⃗, 𝑐 ⃗ are coplanar if [𝒂 ⃗" " 𝒃 ⃗" " 𝒄 ⃗ ] = 0 Finding [𝒂 ⃗" " 𝒃 ⃗" " 𝒄 ⃗ ] [𝑎 ⃗" " 𝑏 ⃗" " 𝑐 ⃗ ] = |■8(1&1&1@1&0&0@𝑐_1&−1&1)| = 1[(0×1)−(0×−1) ] − 1[(1×1)−(𝑐_1×0) ] + 1[(1×−1)−(𝑐_1×0) ] = 1 [0−0]−1[1−0]+1[−1−0] = 0 – 1 – 1 = –2 ∴ [𝑎 ⃗" " 𝑏 ⃗" " 𝑐 ⃗ ] = –2 ⇒ [𝑎 ⃗" " 𝑏 ⃗" " 𝑐 ⃗ ] ≠ 0 Since [𝑎 ⃗" " 𝑏 ⃗" " 𝑐 ⃗ ] ≠ 0, Therefore, 𝑎 ⃗,𝑏,𝑐 ⃗ are not coplanar for any value of c1

Ex 10.5 (Supplementary NCERT) 