Solar Panels have to be installed carefully so that the tilt of the roof, and the direction to the sun, produce the largest possible electrical power in the solar panels.
A surveyor uses his instrument to determine the coordinates of the four corners of a roof where solar panels are to be mounted. In the picture , suppose the points are labelled counter clockwise from the roof corner nearest to the camera in units of meters P 1 (6, 8, 4) , P 2 (21, 8, 4), P 3 (21, 16, 10) and P 4 (6, 16, 10)

Solar Panels have to be installed - Teachoo.jpg

part 2 - Question 1 - Case Based Questions (MCQ) - Serial order wise - Chapter 10 Class 12 Vector Algebra

Question 1

What are the components to the two edge vectors defined by Aย โƒ— = PV of P 2 โ€“ PV of P1 and Bย โƒ— ย = PV of P 4 โ€“ PV of P 1 ? (where PV stands for position vector)

part 3 - Question 1 - Case Based Questions (MCQ) - Serial order wise - Chapter 10 Class 12 Vector Algebra

Question 2

Write the vector in standard notation with iย ฬ‚, jย ฬ‚ ย and kย ฬ‚ (where iย ฬ‚, jย ฬ‚ย  and kย ฬ‚ are the unit vectors along the three axes).

part 4 - Question 1 - Case Based Questions (MCQ) - Serial order wise - Chapter 10 Class 12 Vector Algebra

Question 3

What are the magnitudes of the vectors Aย โƒ— and Bย โƒ— and in what units?

part 5 - Question 1 - Case Based Questions (MCQ) - Serial order wise - Chapter 10 Class 12 Vector Algebra

Question 4

What are the components to the vector Nย โƒ— , perpendicular to Aย โƒ— and Bย โƒ— and the surface of the roof?

part 6 - Question 1 - Case Based Questions (MCQ) - Serial order wise - Chapter 10 Class 12 Vector Algebra

Question 5
What is the magnitude of Nย โƒ— and its units? The sun is located along the unit vector Sย โƒ— ย = 1/2 iย ฬ‚-6/7ย  jย ฬ‚+1/7ย  kย ฬ‚. If the flow of solar energy is given by the vector Fย โƒ—ย  = 910 S in units of watts/meter2 , what is the dot product of vectors Fย โƒ— ๐‘ค๐‘–๐‘กโ„Ž Nย โƒ— , and the units for this quantity?

part 7 - Question 1 - Case Based Questions (MCQ) - Serial order wise - Chapter 10 Class 12 Vector Algebra part 8 - Question 1 - Case Based Questions (MCQ) - Serial order wise - Chapter 10 Class 12 Vector Algebra

Question 6

What is the angle between vectors Nย โƒ— and Sย โƒ— ? What is the elevation angle of the sun above the plane of the roof? (cos 51ยฐ = 0.629 )

part 9 - Question 1 - Case Based Questions (MCQ) - Serial order wise - Chapter 10 Class 12 Vector Algebra

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Question Solar Panels have to be installed carefully so that the tilt of the roof, and the direction to the sun, produce the largest possible electrical power in the solar panels. A surveyor uses his instrument to determine the coordinates of the four corners of a roof where solar panels are to be mounted. In the picture , suppose the points are labelled counter clockwise from the roof corner nearest to the camera in units of meters P1 (6, 8, 4) , P2 (21, 8, 4), P3 (21, 16, 10) and P4 (6, 16, 10)Question 1 What are the components to the two edge vectors defined by ๐ด โƒ— = PV of P2 โ€“ PV of P1 and ๐ต โƒ— = PV of P4 โ€“ PV of P1? (where PV stands for position vector)15, 0, 0 : 0, 8, 6 Question 2 Write the vector in standard notation with ๐‘– ฬ‚, ๐‘— ฬ‚ and ๐‘˜ ฬ‚ (where ๐‘– ฬ‚, ๐‘— ฬ‚ and ๐‘˜ ฬ‚ are the unit vectors along the three axes).15i + 0j + 0k Answer 2: 0i + 8j + 6k Question 3 What are the magnitudes of the vectors ๐ด โƒ— and ๐ต โƒ— and in what units?Answer : 15 meters, Answer : โˆš(8^2+6^2 ) = โˆš(64+36) = โˆš100 = 10 meters Question 4 What are the components to the vector ๐‘ โƒ— , perpendicular to ๐ด โƒ— and ๐ต โƒ— and the surface of the roof?๐‘ โƒ— = ๐ด โƒ— ร— ๐ต โƒ— N = |โ– 8(๐‘–&๐‘—&๐‘˜@15&0&0@0&8&6)| = โ€“15 (6๐‘— โ€“ 8๐‘˜) = โ€“90๐‘— + 120๐‘˜ ; Answer โ€“90 , 120 Question 5 What is the magnitude of ๐‘ โƒ— and its units? The sun is located along the unit vector ๐‘† โƒ— = 1/2 ๐‘– ฬ‚โˆ’6/7 ๐‘— ฬ‚+1/7 ๐‘˜ ฬ‚. If the flow of solar energy is given by the vector ๐น โƒ— = 910 S in units of watts/meter2 , what is the dot product of vectors ๐น โƒ— ๐‘ค๐‘–๐‘กโ„Ž ๐‘ โƒ— , and the units for this quantity?โˆš((โˆ’90)^2+120^2 )= โˆš(8100+14400)=โˆš22500=150 Answer of second part: ๐น โƒ— = 910 (1/2 " " ๐‘– ฬ‚โˆ’6/7 ๐‘— ฬ‚+1/7 ๐‘˜ ฬ‚ ) = 455 ๐‘– ฬ‚ โ€“ 780 ๐‘— ฬ‚ + 130 ๐‘˜ ฬ‚ The dot product is just ๐น โƒ— โˆ™ ๐‘ โƒ— = 455*(0) โ€“780*(โ€“90) + 130*120 = 85,800 watts. From the definition of dot product: ๐น โƒ— โˆ™ ๐‘ โƒ— =| ๐น โƒ—||๐‘ โƒ— |cosฮธ Then since | ๐น โƒ— | = 910 and | ๐‘ โƒ— | = 150 and ๐น โƒ— โˆ™ ๐‘ โƒ— = 85,800 we have cosฮธ = (85800/(910x150)) = 0.629 and so ฮธ =cos-1 (0.629) which is 0.8905 rad and is 51o .(using cosine table) Question 6 What is the angle between vectors ๐‘ โƒ— and ๐‘† โƒ— ? What is the elevation angle of the sun above the plane of the roof? (cos 51ยฐ = 0.629 ) This is the angle between the normal to the surface and the incident solar rays. The compliment of this is the elevation of the sun above the plane of the roof or 90 โ€“ 51 = 39ยฐ .

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