Supplementary Example 1
Last updated at Dec. 8, 2016 by Teachoo
Transcript
Supplementary Example 1 If 𝑎 = 2 𝑖 − 3 𝑗 + 4 𝑘 , 𝑏 = 𝑖 + 2 𝑗 – 3 𝑘 , 𝑐 = 3 𝑖 + 4 𝑗 – 𝑘, then find 𝑎.( 𝑏 × 𝑐) & ( 𝑎 × 𝑏). 𝑐 . Is 𝑎.( 𝑏 × 𝑐) = ( 𝑎 × 𝑏). 𝑐 ? Given, 𝑎 = 2 𝑖 − 3 𝑗 + 4 𝑘 , 𝑏 = 𝑖 + 2 𝑗 – 3 𝑘 , 𝑐 = 3 𝑖 + 4 𝑗 – 𝑘 𝑎.( 𝑏 × 𝑐) = 𝑎 𝑏 𝑐 = 2−3412−334−1 = 2 2×−1−(4×−3) − (−3) 1×−1−(3×−3) + 4 1×4−(3×2) = 2 −2+12+3 −1+9+4 4−6 = 2(10) + 3 (8) + 4(–2) = 20 + 24 – 8 = 36 Finding ( 𝑎 × 𝑏). 𝑐 = 𝑐.( 𝑎 × 𝑏) = 𝑐 𝑎 𝑏 = 34−12−3412−3 = 3 −3×−3−(2×4) − 4 2×−3−(1×4) + (–1) 2×2−(1×−3) = 3 9−8−4 −6−4− 4+3 = 3(1) – 4(–10) – 7 = 3 + 40 – 7 = 36 Hence , 𝑎.( 𝑏 × 𝑐) = ( 𝑎 × 𝑏). 𝑐
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Supplementary Example 3
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Supplementary Exercise Q1
Supplementary Exercise Q2
Supplementary Exercise Q3
Supplementary Exercise Q4
Supplementary Exercise Q5
Supplementary Exercise Q6
Supplementary Exercise Q7
Supplementary Exercise Q8
Supplementary Exercise Q9
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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He provides courses for Mathematics from Class 9 to 12. You can ask questions here.