Supplementary Exercise Q10
Last updated at Aug. 24, 2021 by
Last updated at Aug. 24, 2021 by
Transcript
Supplementary Exercise Q10 If the vectors ๐ด โ = a๐ ฬ + ๐ ฬ + ๐ ฬ, ๐ต โ = ๐ ฬ + b๐ ฬ + ๐ ฬ and ๐ถ โ = ๐ ฬ + ๐ ฬ + c๐ ฬ are coplanar, then 1/(1โ๐) + 1/(1โ๐) + 1/(1โ๐) = 1, where a, b, c โ 1 Since Vectors ๐ด โ, ๐ต โ, ๐ถ โ are coplanar , โด [๐ด โ" " ๐ต โ" " ๐ถ โ ] = 0 [๐ด โ" " ๐ต โ" " ๐ถ โ ] = |โ 8(๐&1&1@1&๐&1@1&1&๐)| 0 = a[(๐ร๐)โ(1ร1) ] โ 1[(1ร๐)โ(1ร1)] + 1[(1ร1)โ(1ร๐) ] 0 = a [๐๐โ1]โ[๐โ1]+1[1โ๐] 0 = abc โ a โ c + 1 + 1 โ b = 0
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Supplementary Example 2 Important Deleted for CBSE Board 2022 Exams
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Supplementary Exercise Q1 Deleted for CBSE Board 2022 Exams
Supplementary Exercise Q2 Deleted for CBSE Board 2022 Exams
Supplementary Exercise Q3 Deleted for CBSE Board 2022 Exams
Supplementary Exercise Q4 Important Deleted for CBSE Board 2022 Exams
Supplementary Exercise Q5 Deleted for CBSE Board 2022 Exams
Supplementary Exercise Q6 Important Deleted for CBSE Board 2022 Exams
Supplementary Exercise Q7 Deleted for CBSE Board 2022 Exams
Supplementary Exercise Q8 Deleted for CBSE Board 2022 Exams
Supplementary Exercise Q9 Important Deleted for CBSE Board 2022 Exams
Supplementary Exercise Q10 Deleted for CBSE Board 2022 Exams You are here
Supplementary examples and questions from CBSE
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