![Supplementary Example 6 - Prove [a+b b+c c+a] = 2 [a b c] - Supplementary examples and questions from CBSE](https://d1avenlh0i1xmr.cloudfront.net/aa337f39-cfb5-4eb2-8782-77a3a9679f24/slide12.jpg)
Supplementary Example 6
Last updated at May 29, 2018 by Teachoo
Transcript
Supplementary Example 6 For any three vectors ∴ 𝑎, 𝑏, and 𝑐, prove that 𝑎 + 𝑏 𝑏+ 𝑐 𝑐+ 𝑎 = 2 [ 𝑎 , 𝑏, 𝑐] To prove 𝑎 + 𝑏 𝑏+ 𝑐 𝑐+ 𝑎 = 2 [ 𝑎 , 𝑏, 𝑐] Solving LHS 𝑎 + 𝑏 𝑏+ 𝑐 𝑐+ 𝑎 = ( 𝑎 + 𝑏). ( 𝑏+ 𝑐) × ( 𝑐+ 𝑎) = ( 𝑎 + 𝑏). ( 𝑏× 𝑐) + ( 𝑏× 𝑎)+( 𝒄× 𝒄) + ( 𝑐× 𝑎) = ( 𝑎+ 𝑏). 𝑏× 𝑐) + ( 𝑏× 𝑎 + 0 + ( 𝑐 × 𝑎) = 𝑎. ( 𝑏 × 𝑐) + 𝑏.( 𝑏 × 𝑐) + 𝑎. ( 𝑏 × 𝑎) + 𝑏.( 𝑏 × 𝑎) + 𝑎.( 𝑐 × 𝑎) + 𝑏.( 𝑐 × 𝑎) = 𝑎, 𝑏, 𝑐 + 𝒃, 𝒃, 𝒄 + 𝒂, 𝒃, 𝒂 + 𝒃, 𝒃, 𝒂 + 𝒂, 𝒄, 𝒂 + 𝑏, 𝑐, 𝑎 = 𝑎, 𝑏, 𝑐 + 0 + 0 + 0 + 0 + 𝑏, 𝑐, 𝑎 = 𝑎, 𝑏, 𝑐 + 𝒃, 𝒄, 𝒂 = 𝑎, 𝑏, 𝑐 + 𝒂, 𝒃, 𝒄 = 2 𝑎, 𝑏, 𝑐 = R.H.S Hence proved
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About the Author
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.