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Supplementary examples and questions from CBSE
Supplementary Example 2 Important Deleted for CBSE Board 2023 Exams You are here
Supplementary Example 3 Deleted for CBSE Board 2023 Exams
Supplementary Example 4 Deleted for CBSE Board 2023 Exams
Supplementary Example 5 Important Deleted for CBSE Board 2023 Exams
Supplementary Example 6 Deleted for CBSE Board 2023 Exams
Supplementary Exercise Q1 Deleted for CBSE Board 2023 Exams
Supplementary Exercise Q2 Deleted for CBSE Board 2023 Exams
Supplementary Exercise Q3 Deleted for CBSE Board 2023 Exams
Supplementary Exercise Q4 Important Deleted for CBSE Board 2023 Exams
Supplementary Exercise Q5 Deleted for CBSE Board 2023 Exams
Supplementary Exercise Q6 Important Deleted for CBSE Board 2023 Exams
Supplementary Exercise Q7 Deleted for CBSE Board 2023 Exams
Supplementary Exercise Q8 Deleted for CBSE Board 2023 Exams
Supplementary Exercise Q9 Important Deleted for CBSE Board 2023 Exams
Supplementary Exercise Q10 Deleted for CBSE Board 2023 Exams
Supplementary examples and questions from CBSE
Last updated at March 16, 2023 by Teachoo
Supplementary Example 2 Find the volume of the parallelepiped whose edges are π β = 2π Μ β 3π Μ + 4π Μ, π β = π Μ + 2π Μ β π Μ and π β = 2π Μ β π Μ + 2π Μ Given, π β = 2π Μ β 3π Μ + 4π Μ , π β = π Μ + 2π Μ β π Μ , π β = 2π Μ β π Μ + 2π Μ Volume of parallelepiped = [π β" " π β" " π β ] = |β 8(2&β3&[email protected]&2&β[email protected]&β1&2)| = 2[(2Γ2)β(β1Γβ1) ] β (β3) [(1Γ2)β(2Γβ1) ] + 4[(1Γβ1)β(2Γ2)] = 2 [4β1]+3(2+2)+4[β1β4] = 2(3) + 3 (4) + 4(β5) = 6 + 12 β 20 = β2 Since volume is always positive Volume of parallelepiped = 2 cubic units