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Supplementary examples and questions from CBSE
Supplementary Example 2 Important Deleted for CBSE Board 2024 Exams You are here
Supplementary Example 3 Deleted for CBSE Board 2024 Exams
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Supplementary Example 5 Important Deleted for CBSE Board 2024 Exams
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Supplementary Exercise Q1 Deleted for CBSE Board 2024 Exams
Supplementary Exercise Q2 Deleted for CBSE Board 2024 Exams
Supplementary Exercise Q3 Deleted for CBSE Board 2024 Exams
Supplementary Exercise Q4 Important Deleted for CBSE Board 2024 Exams
Supplementary Exercise Q5 Deleted for CBSE Board 2024 Exams
Supplementary Exercise Q6 Important Deleted for CBSE Board 2024 Exams
Supplementary Exercise Q7 Deleted for CBSE Board 2024 Exams
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Supplementary Exercise Q9 Important Deleted for CBSE Board 2024 Exams
Supplementary Exercise Q10 Deleted for CBSE Board 2024 Exams
Supplementary examples and questions from CBSE
Last updated at May 29, 2023 by Teachoo
Supplementary Example 2 Find the volume of the parallelepiped whose edges are π β = 2π Μ β 3π Μ + 4π Μ, π β = π Μ + 2π Μ β π Μ and π β = 2π Μ β π Μ + 2π Μ Given, π β = 2π Μ β 3π Μ + 4π Μ , π β = π Μ + 2π Μ β π Μ , π β = 2π Μ β π Μ + 2π Μ Volume of parallelepiped = [π β" " π β" " π β ] = |β 8(2&β3&4@1&2&β1@2&β1&2)| = 2[(2Γ2)β(β1Γβ1) ] β (β3) [(1Γ2)β(2Γβ1) ] + 4[(1Γβ1)β(2Γ2)] = 2 [4β1]+3(2+2)+4[β1β4] = 2(3) + 3 (4) + 4(β5) = 6 + 12 β 20 = β2 Since volume is always positive Volume of parallelepiped = 2 cubic units