Supplementary Example 2
Last updated at Dec. 8, 2016 by Teachoo
Transcript
Supplementary Example 2 Find the volume of the parallelepiped whose edges are 𝑎 = 2 𝑖 − 3 𝑗 + 4 𝑘, 𝑏 = 𝑖 + 2 𝑗 − 𝑘 and 𝑐 = 2 𝑖 − 𝑗 + 2 𝑘 Given, 𝑎 = 2 𝑖 − 3 𝑗 + 4 𝑘 , 𝑏 = 𝑖 + 2 𝑗 – 𝑘 , 𝑐 = 2 𝑖 – 𝑗 + 2 𝑘 Volume of parallelepiped = 𝒂 𝒃 𝒄 = 2−3412−12−12 = 2 2×2−(−1×−1) − (−3) 1×2−(2×−1) + 4 1×−1−(2×2) = 2 4−1+3 2+2+4 −1−4 = 2(3) + 3 (4) + 4(–5) = 6 + 12 – 20 = –2 Since volume is always positive Volume of parallelepiped = 2 cubic units
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Supplementary Exercise Q1
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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He provides courses for Mathematics from Class 9 to 12. You can ask questions here.