Supplementary examples and questions from CBSE
Supplementary Example 2 Important Deleted for CBSE Board 2024 Exams
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Supplementary Exercise Q1 Deleted for CBSE Board 2024 Exams
Supplementary Exercise Q2 Deleted for CBSE Board 2024 Exams
Supplementary Exercise Q3 Deleted for CBSE Board 2024 Exams
Supplementary Exercise Q4 Important Deleted for CBSE Board 2024 Exams
Supplementary Exercise Q5 Deleted for CBSE Board 2024 Exams
Supplementary Exercise Q6 Important Deleted for CBSE Board 2024 Exams
Supplementary Exercise Q7 Deleted for CBSE Board 2024 Exams
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Supplementary Exercise Q9 Important Deleted for CBSE Board 2024 Exams
Supplementary Exercise Q10 Deleted for CBSE Board 2024 Exams
Supplementary examples and questions from CBSE
Last updated at April 16, 2024 by Teachoo
Supplementary Example 3 Show that the vectors 𝑎 ⃗ = −4𝑖 ̂ − 6𝑗 ̂ − 2𝑘 ̂, 𝑏 ⃗ = −𝑖 ̂ + 4𝑗 ̂ + 3𝑘 ̂ and 𝑐 ⃗ = −8𝑖 ̂ − 𝑗 ̂ + 3𝑘 ̂ are coplanar Three vectors 𝑎 ⃗, 𝑏 ⃗, 𝑐 ⃗ are coplanar if [𝒂 ⃗" " 𝒃 ⃗" " 𝒄 ⃗ ] = 0 Given, 𝑎 ⃗ = –4𝑖 ̂ − 6𝑗 ̂ – 2𝑘 ̂ 𝑏 ⃗ = −𝑖 ̂ + 4𝑗 ̂ + 3𝑘 ̂ 𝑐 ⃗ = –8𝑖 ̂ − 𝑗 ̂ + 3𝑘 ̂ [𝑎 ⃗" " 𝑏 ⃗" " 𝑐 ⃗ ] = |■8(−4&−6&−2@−1&4&3@−8&−1&3)| = –4[(4×3)−(−1×3) ] − (−6) [(−1×3)−(−8×3) ] + (–2)[(−1×−1)−(−8×4)] = –4 [12+3]+6(−3+24)−2[1+32] = –4(15) + 6 (21) –2(33) = –60 + 126 – 66 = 0 Since [𝑎 ⃗" " 𝑏 ⃗" " 𝑐 ⃗ ] = 0 Vectors 𝑎 ⃗, 𝑏 ⃗, 𝑐 ⃗ are coplanar