If a = 7i - 2j + 3k, b = i - j + 2k and c = 3i + 8j, then find a.(b×c) - Supplementary examples and questions from CBSE

part 2 - Supplementary Exercise Q1 - Supplementary examples and questions from CBSE - Serial order wise - Chapter 10 Class 12 Vector Algebra

Remove Ads Take short quiz All Quiz and Worksheets
Teachoo ¡ Class 12 Explore Class 12

Transcript

Supplementary Exercise Q1 if 𝑎 ⃗ = 7𝑖 ̂ − 2𝑗 ̂ + 3𝑘 ̂, 𝑏 ⃗ = 𝑖 ̂ − 𝑗 ̂ + 2𝑘 ̂ and 𝑐 ⃗ = 3𝑖 ̂ + 8𝑗 ̂ , then find 𝑎 ⃗ (𝑏 ⃗ × 𝑐 ⃗) and (𝑎 ⃗ × 𝑏 ⃗). 𝑐 ⃗ Also Find whether if 𝑎 ⃗.(𝑏 ⃗ × 𝑐 ⃗) and (𝑎 ⃗ × 𝑏 ⃗).𝑐 ⃗ are equal Given, 𝑎 ⃗ = 7𝑖 ̂ − 2𝑗 ̂ + 3𝑘 ̂ , 𝑏 ⃗ = 𝑖 ̂ – 𝑗 ̂ + 2𝑘 ̂ , 𝑐 ⃗ = 3𝑖 ̂ + 8𝑗 ̂ = 3𝑖 ̂ + 8𝑗 ̂ + 0𝑘 ̂ 𝑎 ⃗.(𝑏 ⃗ × 𝑐 ⃗) = [𝑎 ⃗" " 𝑏 ⃗" " 𝑐 ⃗ ] = |■8(7&−2&3@1&−1&2@3&8&0)| = 7[(−1×0)−(8×2) ] − (−2) [(1×0)−(3×2) ] + 3[(1×8)−(3×−1)] = 7 [0−16]+2(0−6)+3[8+3] = 7(–16) + 2(–6) + 3(11) = –112 – 12 + 33 = –91 Finding (𝑎 ⃗ × 𝑏 ⃗).𝑐 ⃗ = 𝑐 ⃗.(𝑎 ⃗ × 𝑏 ⃗) = [𝑐 ⃗" " 𝑎 ⃗" " 𝑏 ⃗ ] = |■8(3&8&0@7&−2&3@1&−1&2)| = 3[(−2×2)−(−1×3) ] − 8[(7×2)−(1×3) ] + 0[(7×−1)−(1×−2)] = 3[−4+3]−8(14−3)−0 = 3(–1) – 8(11) = –3 – 88 = –91 Hence , 𝒂 ⃗.(𝒃 ⃗ × 𝒄 ⃗) = (𝒂 ⃗ × 𝒃 ⃗).𝒄 ⃗

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh is an IIT Kanpur graduate and has been teaching for 16+ years. At Teachoo, he breaks down Maths, Science and Computer Science into simple steps so students understand concepts deeply and score with confidence.

Many students prefer Teachoo Black for a smooth, ad-free learning experience.