Supplementary Exercise Q1
Last updated at Aug. 24, 2021 by
Last updated at Aug. 24, 2021 by
Transcript
Supplementary Exercise Q1 if ๐ โ = 7๐ ฬ โ 2๐ ฬ + 3๐ ฬ, ๐ โ = ๐ ฬ โ ๐ ฬ + 2๐ ฬ and ๐ โ = 3๐ ฬ + 8๐ ฬ , then find ๐ โ (๐ โ ร ๐ โ) and (๐ โ ร ๐ โ). ๐ โ Also Find whether if ๐ โ.(๐ โ ร ๐ โ) and (๐ โ ร ๐ โ).๐ โ are equal Given, ๐ โ = 7๐ ฬ โ 2๐ ฬ + 3๐ ฬ , ๐ โ = ๐ ฬ โ ๐ ฬ + 2๐ ฬ , ๐ โ = 3๐ ฬ + 8๐ ฬ = 3๐ ฬ + 8๐ ฬ + 0๐ ฬ ๐ โ.(๐ โ ร ๐ โ) = [๐ โ" " ๐ โ" " ๐ โ ] = |โ 8(7&โ2&3@1&โ1&2@3&8&0)| = 7[(โ1ร0)โ(8ร2) ] โ (โ2) [(1ร0)โ(3ร2) ] + 3[(1ร8)โ(3รโ1)] = 7 [0โ16]+2(0โ6)+3[8+3] = 7(โ16) + 2(โ6) + 3(11) = โ112 โ 12 + 33 = โ91 Finding (๐ โ ร ๐ โ).๐ โ = ๐ โ.(๐ โ ร ๐ โ) = [๐ โ" " ๐ โ" " ๐ โ ] = |โ 8(3&8&0@7&โ2&3@1&โ1&2)| = 3[(โ2ร2)โ(โ1ร3) ] โ 8[(7ร2)โ(1ร3) ] + 0[(7รโ1)โ(1รโ2)] = 3[โ4+3]โ8(14โ3)โ0 = 3(โ1) โ 8(11) = โ3 โ 88 = โ91 Hence , ๐ โ.(๐ โ ร ๐ โ) = (๐ โ ร ๐ โ).๐ โ
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Supplementary examples and questions from CBSE
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