Ex 12.1, 27 - Chapter 12 Class 11 Limits and Derivatives

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Ex 12.1, 27 Find lim┬(x→5) f(x), where f(x) = |x| – 5 Finding limit at x = 5 LHL at x → 5 lim┬(x→5^− ) f(x) = lim┬(h→0) f(5 − h) = lim┬(h→0) |5−ℎ| – 5 = lim┬(h→0) (5−ℎ) – 5 = lim┬(h→0) −ℎ = 0 RHL at x → 5 lim┬(x→5^+ ) f(x) = lim┬(h→0) f(5 + h) = lim┬(h→0) |5+ℎ| – 5 = lim┬(h→0) (5+ℎ) – 5 = lim┬(h→0) ℎ = 0 Thus, (𝒍𝒊𝒎)┬(𝐱→𝟓) f(x) = 0

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo