Ex 13.1, 6 - Chapter 13 Class 11 Limits and Derivatives
Last updated at March 9, 2017 by Teachoo
Transcript
Ex 13.1, 6 Evaluate the Given limit: lim x 0 x +1 5 1 x lim x 0 x + 1 5 1 x = 0 + 1 5 1 0 = 15 1 0 = 1 1 0 = 0 0 Since it is of from 0 0 Hence, we simplify lim x 0 x +1 5 1 x Putting y = x + 1 x = y 1 As x 0 y 0 + 1 y 1 Our equation becomes lim x 0 x +1 5 1 x = lim y 1 5 1 y 1 =
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