1. Chapter 13 Class 11 Limits and Derivatives
  2. Serial order wise
  3. Ex 13.1

Ex 13.1, 12 - Chapter 13 Class 11 Limits and Derivatives

Last updated at Nov. 30, 2019 by

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  1. Chapter 13 Class 11 Limits and Derivatives
  2. Serial order wise

    3. Ex 13.1

    Ex 13.2 →

Transcript

Ex 13.1, 12 Evaluate the Given limit: lim┬(x→−2) (1/x + 1/2)/(x + 2) lim┬(x→−2) (1/x + 1/2)/(x + 2) At x = –2, the value of the given function takes the form 0/0 . So, simplifying lim┬(x→−2) (1/x + 1/2)/(x + 2) = lim┬(x→−2) (((2 + x)/2x))/(x + 2) = (𝐥𝐢𝐦)┬(𝐱→−𝟐) 𝟏/𝟐𝐱 Putting x = –2 = 1/(2(−2)) = (−𝟏)/𝟒

Chapter 13 Class 11 Limits and Derivatives
Serial order wise

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.