Last updated at May 29, 2018 by Teachoo

Transcript

Ex 13.1, 22 lim x 2 tan 2x x 2 lim x 2 tan 2x x 2 Putting y = x 2 When x 2 y 2 2 y 0 So, our equation becomes lim x 2 tan 2x x 2 = lim y 0 tan 2 2 + = lim y 0 tan ( + 2 ) = lim y 0 tan 2 = lim y 0 1 . sin 2 cos 2 = lim y 0 sin 2 . 1 cos 2 = lim y 0 sin 2 lim y 0 1 cos 2 Divide & Multiply by 2y = lim y 0 sin 2 2 2 . lim y 0 1 cos 2 = lim y 0 sin 2 2 2 . lim y 0 1 cos 2 = lim y 0 sin 2 2 2 . lim y 0 1 cos 2 = 2 . lim y 0 1 cos 2 = 2 . 1 . lim y 0 1 cos 2 = 2 . lim y 0 1 cos 2 = 2. 1 cos 2(0) = 2 cos 0 = 2 1 = 2

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About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.