Ex 12.1, 25 - Chapter 12 Class 11 Limits and Derivatives

Last updated at May 7, 2024 by

Slide54.JPG

Slide55.JPG

Go Ad-free

Transcript

Ex 12.1, 25 Evaluate lim┬(x→0) f(x), where f(x) = {█(|x|/x@0,)┤, ■8(x≠0@x=0) Finding limit at x = 0 LHL at x → 0 lim┬(x→0^− ) f(x) = lim┬(h→0) f(0 − h) = lim┬(h→0) f(−h) = lim┬(h→0) (|−ℎ|)/(−ℎ) = lim┬(h→0) ℎ/(−ℎ) = lim┬(h→0) −1 = −1 RHL at x → 0 lim┬(x→0^+ ) f(x) = lim┬(h→0) f(0 + h) = lim┬(h→0) f(h) = lim┬(h→0) (|ℎ|)/ℎ = lim┬(h→0) ℎ/ℎ = lim┬(h→0) 1 = 1 Since LHL ≠ RHL ∴ (𝒍𝒊𝒎)┬(𝒙→𝟎) f(x) doesn’t exist

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo