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Last updated at May 29, 2023 by Teachoo
Ex 12.1, 19 - Chapter 13 Class 11 Limits and Derivatives - NCERT Evaluate the Given limit: lim (x→0) x sec x lim (x→0) x sec x (Using sec θ = 1/cosθ ) = lim (x→0) x . 1/cosx = lim (x→0) x/cosx Putting x = 0 = 0/(cos 0) = 0/1 (cos 0 = 1) = 0