Ex 13.1, 16
Last updated at March 9, 2017 by Teachoo
Transcript
Ex13.1, 16 Evaluate the given limit: limx→0 cosxπ −x limx→0 cosxπ −x Putting x = 0 = cos0𝜋 − 0 = cos0𝜋 = 𝟏𝛑
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