Ex 13.1, 20 - Chapter 13 Class 11 Limits and Derivatives (Term 1 and Term 2)
Last updated at May 4, 2020 by Teachoo
Transcript
Ex 13.1, 20 Evaluate the Given limit: limβ¬(xβ0) (π ππβ‘ππ₯ + ππ₯)/(ππ₯ + π ππβ‘ππ₯ ) a , b, a + b β 0 limβ¬(xβ0) (π ππβ‘ππ₯ + ππ₯)/(ππ₯ +γ π ππγβ‘ππ₯ ) = limβ¬(xβ0) π₯(π ππβ‘ππ₯/π₯ + π)/π₯(π + π ππβ‘ππ₯/π₯) = limβ¬(xβ0) ((π ππβ‘ππ₯/π₯ ) + π)/(π + ( π ππβ‘ππ₯/π₯) ) Multiply & Divide by π ππβ‘ππ₯/π₯ by ax & Multiply & Divide π ππβ‘γπ₯ γ/π by bx = limβ¬(xβ0) ((π ππβ‘ππ₯/π₯ . ππ₯/ππ₯ ) + π)/(π + ( π ππβ‘ππ₯/π₯ . ππ₯/ππ₯) ) = limβ¬(xβ0) ((π ππβ‘ππ₯/ππ₯ . ππ₯/π₯ ) + π)/(π + ( π ππβ‘ππ₯/ππ₯ . ππ₯/π₯) ) = limβ¬(xβ0) ((πππβ‘ππ/ππ). π + π)/(π + ( πππβ‘ππ/ππ) π) Using limβ¬(xβ0) (sinβ‘x )/x = 1 Replacing x by ax. limβ¬(xβ0) sinβ‘ππ₯/ax = 1 Replacing x by bx limβ¬(xβ0) (sinβ‘bx )/bx = 1 = ((π) π + π)/(π +(π)π) = (π + π)/(π + π) = 1
Ex 13.1 (Term 1)
Ex 13.1, 1
Ex 13.1, 2
Ex 13.1, 3
Ex 13.1, 4 Important
Ex 13.1, 5
Ex 13.1, 6 Important
Ex 13.1, 7
Ex 13.1, 8 Important
Ex 13.1, 9
Ex 13.1,10 Important
Ex 13.1, 11
Ex 13.1, 12
Ex 13.1, 13
Ex 13.1, 14 Important
Ex 13.1, 15 Important
Ex 13.1, 16
Ex 13.1, 17 Important
Ex 13.1, 18
Ex 13.1, 19 Important
Ex 13.1, 20 You are here
Ex 13.1, 21 Important
Ex 13.1, 22 Important
Ex 13.1, 23
Ex 13.1, 24
Ex 13.1, 25 Important
Ex 13.1, 26
Ex 13.1, 27
Ex 13.1, 28 Important
Ex 13.1, 29
Ex 13.1, 30 Important
Ex 13.1, 31
Ex 13.1, 32 Important
Chapter 13 Class 11 Limits and Derivatives (Term 1 and Term 2)
Serial order wise
About the Author
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.