Limits and Derivatives Class 11

Master Limits and Derivatives Class 11 with comprehensive NCERT Solutions, Practice Questions, MCQs, Sample Papers, Case Based Questions, and Video lessons.

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NCERT Solutions

Limits and Derivatives Class 11 – NCERT Solutions

Each question below opens its complete step-by-step Teachoo solution.

Ex 12.1

32 questions

Ex 12.1, 1

Ex 12.1, 1 teackhoo
Evaluate the Given limit: lim x+3
limx +3
Putting x = 3
=34+3
=6

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Ex 12.1, 2

Ex 12.1, 2 teackhoo
. er 22
Evaluate the Given limit: lim (x = 2)
x7.

: 22
lim (x = =)
XO 7
Putting x ="

=q—2

= 7

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Ex 12.1, 3

teackoo
Ex 12.1, 3
Evaluate the Given limit: lim Tr?
re

lim rr?
rol
Puttingr =1

= 1 (1)

=1

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Ex 12.1, 4

teackoo
Ex 12.1, 4
. a ye AK +3
Evaluate the Given limit: lim ==
x04 K¥—-2
. 4x +3
lim ——_
x04 X-2
Putting x =4
_4(4) +3
~ 4-2
_164+3
~ 2
_19
~ 2

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Ex 12.1, 5

Ex 12.1, 5 teachoo
10 5
Evaluate the Given limit: lim “7***
xo-1 x-1
x Exe HT
lim. ————
KO-1 x-1
Putting x =—-1
_ (40+ C198 41
" (4ajy-4
1-141
“4-1
_O+1
~~ 2
1
~ 2

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Ex 12.1, 6

teackoo
Ex 12.1, 6
SL
Evaluate the Given limit: lim S42
x0 x
5
lim (+1)? -1
x30 x
_ (0+4+1)*-1
~ 0
i -1
ar)
_ 1-1
ar)
=?
a)
ran 0
Since it is of from a
Hence, we simplify

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Ex 12.1, 7

Ex 12.1,7 teackoo
1,
. . as 3K? —K-10
Evaluate the Given limit: lim ——_—
x22 x’ -4
. 3x7-x-10
lim —W——_
x02 x" -4
_ 3x27-2-10
~ 22-4
_3x4-2-10
“44
_ 12-12
“4-4
_9
a)
Since it is of form a

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Ex 12.1, 8

teackoo
Ex 12.1, 8
A aaa ye 4-81
Evaluate the Given limit: lim ————
x33 2x° —5x-3

lim —7 —*4
x53 2x? -5x-3
Putting x = 3

_ (3)*-81

~ 23) -5()-3

_ 81-81

“48-15-3

_o

a)

. a 0 ar

Since it is a 3 form, we simplify as

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Ex 12.1, 9

Ex 12.1,9 teachoo
Evaluate the Given limit: lim axed
x30 cxt1
. axtb
lim ——
xo0 cx +1
Putting x =0
_a(0) +b
~ ¢(0) +1
_O+b
“O+F1
_b
“4
=b

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Ex 12.1,10

Ex 12.1, 10 teackoo
1
. a 2871
Evaluate the Given limit: lim —=——
zol 76-1
1
. Z3-1
lim TT
zZo1 26-1
1
(13-1
=a
(1)6 -1
_i-41
“4-1
a)
a)
ag 0
Since it is form 0

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Ex 12.1, 11

teackoo
Ex 12.1, 11 a
2
Evaluate the Given limit: lim oes atb+c#+0
x1 cx’+bx+a
. ax? t+bxtc

lim ———
x1 cx*+bx+a
Putting x =1

_ a(1)? +b) +

~ ¢(4)? + ba) +a

_atbte

“atbte

=1

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Ex 12.1, 12

Ex 12.1, 12 teackoo
Evaluate the Given limit: lim. —
x7-2xKX+2
lim. +
x2-2x+2
. . 0
At x =—2, the value of the given function takes the form .
So, simplifying
1 1 2Z+x
a42 2+x
lim ¥~= lim Ge) x)
x2-2xX+2 x35-2 x+2
. 1
= lim —
x72 2x
Putting x = —2
1
~2(-2)
_ -1
~ 4

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Ex 12.1, 13

Ex 12.1, 13 teackhoo
Evaluate the Given limit: lim ——~
x0 ~bx
. sin ax
lim ——
x20 bx
. . 1
=lim sin ax x—
x0 bx
Multiplying & dividing by ax
. . 1 ax
=lim sin ax x— x—
x0 bx ax
. sinax ax
= lim —— x—
x20 ax bx
. sinax a
= lim —— x—
x20 ax b
a . sinax
=— x lim —
b x-0 ax

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Ex 12.1, 14

Ex 12.1, 14 teackoo
Evaluate the Given limit: lim a a,b #0
x 0 sin bx
li sin ax
sim sin bx
=lim sin ax x lim —
x0 x0 sin bx
Multiplying & dividing by ax
. sin ax . ax
= lim — x lim —
x30 ax x 0 sin bx
=1x lim—_
x0 sin bx sin x
Using lim —— =1
= lim mos
~ x00 sin bx :
Replacing x by ax
Multiplying & dividing by bx lim sin ax _ 1
x30 ax
=li ax, bx
~ ime sin bx bx

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Ex 12.1, 15

Ex 12.1, 15 teackhoo
Evaluate the Given limit: lim “2 2—
xom (TT — x)
lim sin (™ — x)
xOnm (1 — xX)
Lety=m —-x
So, when x > 1
yorn-n
y>o
So, our equation becomes
.__ Sin (1 —x) . siny
lim —— =lim—
xn W(t —x) yoo ny

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Ex 12.1, 16

Ex 12.1, 16 teachoo
. ge COS XK
Evaluate the given limit: lim ——
x70 T —-xX
. COSX
lim —
x70 1 —X
Putting x =0
_ cos 0
“#-0
_ cos 0
ae:
_1
— (cos0 = 1)

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Ex 12.1, 17

Ex 12.1, 17 teackoo
. a 2x1
Evaluate the Given limit: lim <<~—
x00 cosx-1
. cos2x—1
lim ————_
x70 cosx-1
: 2eos?x-1)-1 .
= lim Goo zaU=" (Using cos 2x = 2cos? x - 1)
x00 cosx —
. 2eos?x-1-1
= lim —W——
x0 cosx-1
. 2c0s*x —2
= lim —————_
x30 cosx-1
. 2(cos?x-1 . .
= lim 2(cos” x— 1) Using sin? x = 1 —cos? x
0 1 9
x90 cosx—
._ 2(cos? x — 1?
= lim 2608 = 1)
x90 cosx-1

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Ex 12.1, 18

Ex 12.1, 18 teachoo
Evaluate the Given limit: lim ==?" *
x00 ~bsinx
... ax+xcosx
lim —————_
x90. = =bsinx
- X (a+ cos x)
= lim ——_——
x00 b sinx
= lim oe“ x x )
x70 b sin x
: a+ cos x) sin x
x0 b x
. at+cosx . sinx
=lim (eo) + (lim =)
x70 b x0 x
. a+cosx i
= lim Ss) +1 (Using lim “2% = 1)
x30 b x00 x

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Ex 12.1, 19

Ex 12.1, 19 teackhoo
Evaluate the Given limit: lim x sec x
x00
lim x sec x
x70
=limx. — i a
~ ¥50 * cos x (Using secO=— =)
. x
=lim —
x-0 cosx
Putting x=0
an)
~ cos 0
0
= - cosO=1
7 ( )
=0

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Ex 12.1, 20

Ex 12.1, 20 teachoo
Evaluate the Given limit: lim Smanyhe a,b,a+b+#0
x00 ax + sin bx
.. Sinax + bx
lim ————
x30 ax + sin bx
‘sin ax
x50 x(a + sin >)
x
‘sin ax
= lim Ce )+e x ) *°
sin bx
a (BP)
Multiply & Divide by == by ax
& Multiply & Divide _— by bx
sinax ax
=lim ( x a) +b
sin bx bx
x0 a +( x a)

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Ex 12.1, 21

Ex 12,1, 21 (Method 1) teackoo
Evaluate the Given limit: lim (cosec x — cot x)
x7
lim (cosec x — cot x)
x70
: 1 cos x : _ 1
=lim (= - <*) Using cosec 8 =—— @
x30 \sinx sin x sm
cot 6 = cos
. 1-cosx sin @
= lim ————_
x00 sinx
Putting x=0
_ 1-—cos0O
~ sind
_i-1
~ 0
_ 0
a)

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Ex 12.1, 22

Ex 12.1, 22 teackhoo
. tan 2x
lim. —>+
xo Et x- >
2 2
: tan 2x
lim ——
xO E-F
2 2
Putting y =x -
When x > 5
5 =_=
Yr a3
y>o
So, our equation becomes

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Ex 12.1, 23

Ex 12.1, 23 (Method 1} teackoo
Find lim f(x) and lim f(x), where f(x)
x00 xo1
_f 2x43. x <0
~)3(%+1), x>0
Finding limit at x = 0
Hing Fo) = Jin 0) = Ta
LHLatx > 0 RHL at x > 0
ign 9 Li 0
= lim (2x + 3) = lim 3(x +1)
= 2(0)+3 = 3(0+1)
=0+3 = 3(1)
=3 =3

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Ex 12.1, 24

teackoo
Ex 12.1, 24 (Method 1)
ae _fx—-1, x <1
Find lim f(x), where f(x) = {2 -1,x>1
The Limit at x = 1 will be
dim fad = Jim. fx) = ir, fo)
LHLatx>1 RHLatx->1
Hint dirt
=li 28 = li -x2-
jim x? -1 lim (-x? - 1)
=(1)°-1 =-(1)-1
=1-1 =-1-1
=0 =-2
Thus, lim, f(x) 4 lim f(x)

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Ex 12.1, 25

Ex 12.1, 25 teackoo
tl x #0
Evaluate lim f(x), where f(x) =4 x ,
x30 0, x=0
Finding limit at x = 0
LHL atx -0 RHL atx ~0
Jim f(x) = lim f(O- h) Jim, f(x) = lim f(0 + h)
= fing) = fing
ERI _ lal
= lim —_ = lim —
ho-0 —h ho0 A
h h
= lim — =lim—
h>0 —h hoo h
=lim-1 =lim1
hoo h>0
=-1 =1

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Ex 12.1, 26

Ex 12.1, 26 teackoo
aT 0
Evaluate lim f(x), where f(x) = fs, xX#
x0 0, x=0
Finding limit at x = 0
LHL atx > 0 RHL atx >0
Jim. f(x) = lim f(0- h) Jim, f(x) = lim f(0 + h)}
= lim {(-h) = lim f(h)
. Th A
= lim — = lim —
h-0 |—-hAl h>0 [A]
—h h
= lim — =lim—
ho0 h hoo h
= lim -1 =lim1
h>o h-0
=-1 =1

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Ex 12.1, 27

Ex 12.1, 27 teackoo
Find lim f(x), where f(x) = |x| —5
xO.
Finding limit at x = 5
LHLatx—> 5 RHLatx>5
Jim. f(x) = lim #(5 -h) Jim, f(x) = lim f(5 +h)
= lim [5 —hA|-5 =lim |[5+A|-5
h30 hoo
=lim(S—h)-5 =lim(S+h)-5
=lim—h =limh
h30 h>0
=0 =0
Thus, lim f(x) = 0
x05

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Ex 12.1, 28

teackoo
Ex 12.1, 28
at+tbx, x<1
Suppose f(x) =< 4, xX = 1 and if lim f(x) = f(1) what are
b-—ax, x>1 xl
possible values of a and b?
Here, limit exist at x > 1
ie., LHL = RHL = f(1) = 4 (1)
LHLatx->1 RHLatx->1
jim. f(x) = lim f(1-h) jim, f(x) = lim f(1 +h)
=lima+b(1-h) = lim b-a(1+h)
h30 h50
=a+b(1-0) =b-a(1+0)
=atb (2) =b-a ...(3)

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Ex 12.1, 29

Ex 12.1, 29 teachoo
Let aj, a,....., a, be fixed real numbers and define a function
F(x) = (x — ay) (X— ap)... (X- ay)
What is lim f(x)? For some a # aj, ap......a,, compute lim f(x).
XPay xv-a
f(x) = (x — a4) (X — a5) «(x — ay)
Calculating lim f(x)
x7 ay
lim f(x) = lim (x-a,) (x-a))..... (k-a,)
Xa, Xa,
Putting x= a,
= (a, — a,) (a, — a9) .....(€)— ay)
=0x (a,-4a))...... (a, -—a,)
=0

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Ex 12.1, 30

Ex 12.1, 30 teackhoo
Ix] +1, x<0
If f(x) = 4 0 x=0.
Ix] -1, x>0
For what value (s) of a does lim ffx) exists?
xra
We need to find value of a for which lim f(x) exists
xX-~a
We check limit different values of a
* Whena=0
* Whena<0O
* Whena>O
Case 1: When a=0

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Ex 12.1, 31

Ex 12.1, 31 teachoo
; toe - f(x)-2 .
If the function f(x) satisfies lim —~— =, evaluate lim f(x).
xo. x -1 xo
Given
. -2
lim [@)~? =
x71 x*4-1
By Algebra of limits
lim £2). - 28a
ea g(x) lim g(x)
xoag pm g
lim f@) 2 _
lmo2-1
xOL
lim (f(x) - 2) = nx Lim (x? - 1)
xo1 xol
lim f(x) — lim 2 = n (lim x? - lim 1}
xol1 xol1 xo1 xol1

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Ex 12.1, 32

Ex 12.1, 32 teachoo
mx? +n, x<0
If f(x) = 4 nx +m 0<x< 1. For what integers mand n
nx? + m, x>1
does lim f(x) and lim f(x) exist?
x00 xo1
Given limit exists at x =O and x=1
Atx=0
Limit exists at x = 0 if
Left hand limit = Right hand limit

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Ex 12.2

27 questions

Ex 12.2, 1

Ex 12.2, 1 teackoo
Find the derivative of x? -2 atx = 10.
Let f (x)= x7-2
py — x? — 2)
P(x) =~
=2x-0
=2x
So, f’(x) = 2x
f’(10) = 2x 10
=20

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Ex 12.2, 2

Ex 13.2, 2 teachoo.com
Find the derivative of x at x = 1.
Let f (x) =x
We need to find derivative of f(x) at x = 1
ie. f’ (1)
We know that
. h)—
(9 = lim Le EW ALO
h70 h
Here, f(x} = x
So, f(x+h)=x+h

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Ex 12.2, 3

Ex 12.2, 3 teachoo
Find the derivative of 99x at x = 100
Let f (x) =x
We need to find derivative of f(x) at x = 100
i.e. f’ (100)
We know that
. +h)-
f’ (x) = lim£& ) — f )
ho0 h

Here, f(x) = 99x

f(x + h) = 99(x + h) = 99x + 99h

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Ex 12.2, 4 (i)

Ex 12.2, 4 teachoo
Find the derivative of the following functions from first principle.
(i) 8-27
Let f(x) =x? - 27
We need to find Derivative of f(x)
ie. f” (x)
We know that

” _ Lee (OK +h) - FC”)

Fea) = fig
Here, f (x) = x? -— 27

f(x +h) =(x+ h)?-27

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Ex 12.2, 4 (ii)

Find the derivative of the following functions from first principle.
(ii) (x – 1) (x – 2)

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Ex 12.2, 4 (iii)

Find the derivative of the following functions from first principle.
(iii) 1/𝑥^2

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Ex 12.2, 4 (iv)

Find the derivative of the following functions from first principle.
(iv) (𝑥 + 1)/(𝑥 − 1)

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Ex 12.2, 5

Ex 12.2, 5 teachoo
; ery 2
For the function f(x} = — + — +....4—+x+ 1. Prove that f’(1} = 100
100 = =©100 2
f(0)
We have
100 99 x2 (x")’ = nxe-t
f (x) =——+— +... + —4+x41 ,
100 99 2 & {a)’=0
where a is constant
1 1 1 '
f* (x) = (= x1004 — X99 HS AE XE 1)
100 99 2
y 1 100-1 1 99-1 1 2-1 1-1
f’ (x) = — x 100x + — x 99x +. b= & 2x2-14 1.1140
100 99 2
100 99 2
= — x99 + — x98 4 t-te x0 40
100 99 2
= x99 4 x94 Xt 140
= x99 498 + +x +1

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Ex 12.2, 6

Ex 12.2, 6 teackhoo
Find the derivative of x" + ax"? + a2x"+....+ a" x + a" for some fixed
real number a.
Let f (x) = x" + ax"-1+4 a2x"~24,,..4 a? 1x + a" (where a is constant)
(x?)’=nx?-2
f? (x) = (xP + axn tt a2xh2ht an 1X + an)’ & (a)’=0
where a is constant
=n.x" 14 a(n — px 9-14 a2 (mn — 2px ot.
+a"? (1pco1+0
= nx? t+ a(n — 1)x?-2 + a2 (n—2)x 9-3 +... ah 4 (1)(1)
=nx""14a(n—1)x"-2 4. a2 (n—-2)x "3 4... 4¢an-2
of) = nx" 1 4 a(n —1)x"-2 + a2 (n—-2)x "3 + tant

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Ex 12.2, 7 (i)

Ex 12.2, 7 (Method 1) teachoo
For some constants a and b, find the derivative of
(i) (x— a) (x—b)
Let f (x) = (x-a) (x—b)
=x(x-b)-a(x-b)
= x?—xb—ax tab
=x?—(b+a)x + ab
Oey = nxr-t
f’(x) = (x? - (b +. a)x + ab)’ & (a)’=0
=2.x21-(b+a).Dd1+0
= 2xt-(b +a). x°
=2x-(bt+a)x1
= 2x—-(b+a)

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Ex 12.2, 7 (ii)

For some constants a and b, find the derivative of
(ii) (ax2 + b)2

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Ex 12.2, 7 (iii)

For some constants a and b, find the derivative of
(iii) (x − a)﷮(x − b)﷯

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Ex 12.2, 8

Ex 12.2, 8 teachoo
n_ an

Find the derivative of — for some constant a.
We need to find derivative of —

x "— a?
Let f(x) = yea
Let u=x"-a"&v=x-a

u
So, f(x) = (“)
0, F(x) = {—
fay aol
f(x) = u 7 u

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Ex 12.2, 9 (i)

Ex 12.2, 9 teackhoo
Find the derivative of
(i) 2x - =
3
Let f(x) = 2x -=
4
, d(2x -)
f(x) = —
= 2-0
=2
2 f(xj=2

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Ex 12.2, 9 (ii)

Find the derivative of
(ii) (5x3 + 3x – 1) (x – 1)

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Ex 12.2, 9 (v)

Find the derivative of
(v) f (x) = x–4 (3 – 4x–5)

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Ex 12.2, 9 (vi)

Find the derivative of
(vi) f(x) = 2/(x + 1) – x2/(3x − 1)

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Ex 12.2, 10

Ex 12.2, 10 teachoo
Find the derivative of cos x from first principle.
Let f (x)= cos x
We need to find f’(x)
We know that
. h)-
f(x) = lim fat h)- f@)
hoo h
Here, f (x) = cos x
f (x + h) = cos (x +h)
Putting values,

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Ex 12.2, 11 (i)

Ex 12.2, 11 teackhoo
Find the derivative of the following functions:
(i) sin x cos x
Let f (x) = sin x cos x.
Let u=sinx

&v=cosx
« f(x) = uv
So, f(x} = (uv)’

=uvtv'u
Here, u=sinx
u’ = cos x (Derivative of sin x = cos x)

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Ex 12.2, 11 (ii)

Find the derivative of the following functions:
(ii) sec x

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Ex 12.2, 11 (iii)

Find the derivative of the following functions:
(iii) 5 sec x + 4 cos x

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Ex 12.2, 11 (iv)

Find the derivative of the following functions:
(iv) cosec x

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Ex 12.2, 11 (v)

Find the derivative of the following functions:
(v) f (x) = 3cot x + 5cosec x.

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Ex 12.2, 11 (vi)

Find the derivative of the following functions:
(vi) f (x) = 5sin x – 6 cos x + 7.

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Ex 12.2, 11 (vii)

Find the derivative of the following functions:
(vii) f (x) = 2 tan x – 7 sec x

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Examples

34 questions

Example 1 (i)

Example 1 teachoo.com

Find the limits:

(i) Lim [x3 — x2 + 1]

x1

lim [x3 — x? + 1]

xXOL

Putting x = 1
=(1P-(1P +1
=1-1+1
=0O+1
=1

View solution

Example 1 (ii)

Example 1
Find the limits:
(ii) (𝑙𝑖𝑚)┬(𝑥→3)⁡〖 [𝑥(𝑥+1)]〗

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Example 1 (iii)

Example 1
Find the limits:
(iii) (𝑙𝑖𝑚)┬(𝑥→−1)⁡〖[1+𝑥+𝑥2+…..+𝑥10]〗

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Example 2 (i)

Example 2 teachoo.com
Find the limits:
ype 241
(i) Lim [|
x1 Lx + 100

lim [+]
xo1 Lx + 100.
Putting x =1

_ vet

~1+100

_att

~ 401

2.

~ 101

View solution

Example 2 (ii)

Example 2
Find the limits:
(ii) (𝑙𝑖𝑚)┬(𝑥→2) [(𝑥^3 − 4𝑥^2 + 4𝑥)/(𝑥^2 − 4)]

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Example 2 (iii)

Example 2
Find the limits:
(iii) lim┬(x→2) [(x2 −4)/(x3 − 4x2 + 4x)]

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Example 2 (iv)

Example 2
Find the limits:
(iv) lim┬(x→2) [(x3 −2𝑥2)/(x2−5x+6)]

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Example 2 (v)

Example 2
Find the limits:
(v) lim┬(x→1) [(x −2)/(x2−x)− 1/(𝑥3 −3𝑥2+2𝑥)]

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Example 3 (i)

teackoo.com
Example 3
Evaluate:
xi
i) lim =
ti xot xt? 4
. x4
lim arr
xo1 x -1
_ ay -1
~ (1)10 -4
_1-1
“4-4
2
“0
a 0
Since it is form .

View solution

Example 3 (ii)

Example 3
Evaluate:
(ii) (𝑙𝑖𝑚)┬(𝑥→0) (√(1 + 𝑥) − 1)/𝑥

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Example 4 (i)

teachoo.com
Example, 4
Evaluate:
+y ys... SiN 4x
(i) lim ——
x00 Sin 2x
.. sin 4x
lim —_!
x 0 sin 2x
= lim sin 4x x lim ——
x00 x00 sin 2x
Multiplying & dividing by 4x
. . Ax + 1
= lim sin 4x .— x lim ——
x00 Ax x00 sin 2x
.. sin4x : 1
= lim ——. 4x x lim ——
x00 4x x00 sin 2x
. sin 4x . . 1
= lim —— x lim 4x x lim ——
x00 4x x70 x00 sin 2x
1 Using lim asi
. . QO x
=1x lim 4x x lim —— ~~
x0 x30 sin 2x Replacing x by 4x
in 4x
lim 2 = 3
x30 4x

View solution

Example 4 (ii)

Example 4
Evaluate:
(ii) lim﷮x→0﷯ tan﷮x﷯﷮x﷯

View solution

Example 5

teachoo.com
Example 5
Find the derivative at x = 2 of the function f(x) = 3x.
f (x) = 3x
We know that,
’ ye, fx+h)-f(x)
f’(x) = lim —
Now, f(x) = 3x
So, f(x + h} = 3 (x +h}
’ _ yn, 30 +h) - 3 &)
f’ (x) = lim Ss
Putting x = 2
pray, 3(2 +h) -3 (2)
f’ (2) = lim —_

View solution

Example 6

feachoo.com
Example 6 (Method 1)
Find the derivative of the function f(x) = 2x2+ 3x-5 atx= -1.
Also prove that f’(0) + 3f’(—1) =0.
Given f(x) = 2x2 + 3x-5
We know that
’ . f(x +An)—-f(x)

f’(x) = lim ————>
Now f (x) = 2x? + 3x-5
So, f (x +h) = 2(x +h)? + 3(x+h)-5
Putting values

2 - - 2 =-

f’ (x) =lim (2(¢ +h)? + B(x +h) - 5) — (2x2 4+ 3x -5)

h-0 h

View solution

Example 7

Example 7 teachoo.com
Find the derivative of sin x at x =0.
Let f(x) = sin x
We know that
He) = Tin, Ft) - FO)
i
Here,
f(x) = sin x
f(x + h) = sin (x + h)
Now,

View solution

Example 8

Example 8 teachoo.com
Find the derivative of f(x) = 3 at x = O and at x =3.
f(x) = 3
We need to find
Derivative of f(x) atx =0 & atx =3
i.e. f? (0) & f’ (3)
We know that

f(x) =lim f(x +h) - f(x)

hoo h

Here, f (x) =3
So, f (x +h} =3
Putting values

“1y) = Jim 222

rs) = m5

View solution

Example 9

Example 9 teachoo.com
Find the derivative of f(x} = 10x.
Let f (x) = 10x
We need to find derivative of f(x)
ie. f’ (x)
We know that

f(x) = lim f(x +h) - f(x)

hoo h
Here, f {x} = 10x
So, f (x + h) = 10({x + h)
Putting values
f’ (x) = lim 10(x +h) -10x
ho0 h

View solution

Example 10

feachoo.com
Example 10
Find the derivative of f(x) = x2.
Given f(x) = x?
We need to find derivative of f(x)
ie. f? (x)
We know that
f’(x) = lim f(x +h) — fG)

h-0 h
Here, f (x) = x?
So, f (x +h) = (x +h)?
Putting values

View solution

Example 11

teachoo.
Example 11 faemoo ton
Find the derivative of the constant function f (x) = a for a fixed real
number a.
Given f (x) =a
»where ais constant
thus, f(x) is a constant function
We need to find derivative of f(x)
i.e. f’ (x)
We know that
, . f(x +h) - f()
f(x) = Jim ————>
(x) = jim h
Here, f {x}=a
So, f (x+h)=a

View solution

Example 12

Example 12 teachoo.com
Find the derivative of f(x) =*
1
f (x)= =
We need to find Derivative of f(x)
ie. f (x)
We know that
f(x) = lim f(x +h) - f(x)
h-0 h
1
Here, f (x) = :
So, f (x +h) = a
(x +h)

Putting values

View solution

Example 13

teachoo.com

Example 13
Compute the derivative of 6x1 — x55 + x,
Let f (x) = 6x100 — x95 + x
We need to find f’ {x}
#7 (x) = 6 (100) x199-1— 5555-144, xt-1 (As (x°)’ = nx°-4)

= 600x°9 — 55x 54+ x?

= 600x°? — 55x54 + 1

View solution

Example 14

feachoo.com
Example 14
Find the derivative of f(x) =1+x+x? 4x3 +..4x°% at x= 1.
We need to find f’ {x} at x = 1
ie. f’ (1)
f(x) = 14+ xX4x7 4x3 to, OP
f(x) = (1 tx x72 $8 to # OO) Oey = nxr-t
f’(x) = OF D.xbt + 2x24 4 3x32 tose + 50X01 & (a)'=0
where a is constant
= 1+ 2x + 3x? tu. + 50X49
Hence,
f (x) =14+ 2x + 3x2 +... + 50x

View solution

Example 15

Example 15 (Method 1) feachoocom
Find the derivative of f(x) = =
x+1
f(x) = 224
x 1
on
x x
=1+ 1
x
=1+(x)*
Now,
f’ (x) = (1 + (x) 7)
(x) = (1+ 00) ey oma
=0+(-1)x7>1 & (a)’=0
= 0-x where a is constant
= —-x?
_-1
we

View solution

Example 16

Example 16 teachoo.com
Compute the derivative of sin x.
Let f (xj = sin x
We need to find f’(x)
We know that
, f(x +h) - f(x)
f’(x) = lim ————>
Here, f (x) = sin x
So, f (x +h) = sin (x +h)
Putting values
#’(x) = lim St = sin x
x) noo h

View solution

Example 17

Example 17 teackoo.com
Compute the derivative tan x.
Let f(x) = tan x
We need to fina f’ {x)
We know that
f’(x) =lim f(x + h) — £ (x)
h>0 Rh
Here,
f(x) = tan x
f(x + A) =tan (x +h)
Putting values

View solution

Example 18

feachoo.com
Example 18
Compute the derivative of f(x) = sin? x.
Let f(x) = sin? x
f(x) = sin x sin x

Let u=sinx &v=sin x
So, f(x) = uv
Now,

(x) = (uvy’
Using Product rule

f(x) =u’v + vu

View solution

Example 19 (i)

Example 19 teachoo.com
Find the derivative of f from the first principle, where f is given by
. 2x +3
(i) fq =
We need to find Derivative of f(x)
ie. f’ (x)
We know that
Hy) = Hin FAM F@)
F(x) = im SS
2x4+3
Here, f(x) =o
2 +h) +3
So, f (x +h) = G2

View solution

Example 19 (ii)

Example 19
Find the derivative of f from the first principle, where f is given by
(ii) f(x) = x + 1/x

View solution

Example 20 (i)

Example 20 teackoo.com
Find the derivative of f(x) from the first principle, where f(x) is
(i) sin x + cos x
Given f (x) = sin x + cos x
We need to find Derivative of f(x)
We know that
h =
) = lim LEED =F)
h>0 h

Here,

f (x) = sin x + cos x

f (x +h) =sin (x +h) + cos (x + h)

View solution

Example 20 (ii)

Example 20 teachoo.com
Find the derivative of f(x) from the first principle, where f(x) is
(ii) x sin x
Given f (x) =x sin x
We need to find Derivative of f(x)
We know that
h =
FG) = lim LEED = FO)
h>0 h
Here, f (x) =x sin x
So, f (x+h}= (x +h) sin (x +h)
Putting values

View solution

Example 21 (i)

teachoo.

Example 21 eachoo.com
Compute derivative of
(i) f(x) = sin 2x
Let f (x} = sin 2x

= 2 sin x cos x
Let u=2sinx &v=cosx
So, f(x) = uv
+ #'(x) = (uv)’

=uvetv'u

View solution

Example 22 (i)

Example 22 teackoo.com
Find the derivative of
. x5 —-cosx
(i) sin x
x? —-cosx
Let f(x) = —————
sinx
Let u=x°-—cosx &v=sinx
uu
So, f(x) = ()
w=)
o xp= 7"
Using quotient rule

View solution

Example 22 (ii)

Example 22
Find the derivative of
(ii) (𝑥 + 𝑐𝑜𝑠⁡𝑥)/𝑡𝑎𝑛⁡𝑥

View solution

Miscellaneous

33 questions

Misc 1 (i)

Misc 1 teachoo.com
Find the derivative of the following functions from first principle:
(i) -x
Let f (xj =-—x
We need to find derivative of f(x}
ie. f’ (x}
We know that

f(x) = lim fGcth)- fF)

ho h

Here, f (x) =—x
So, f (x +h) =— (x +h)

View solution

Misc 1 (ii)

Misc 1
Find the derivative of the following functions from first principle:
(ii) (−𝑥)^(−1)

View solution

Misc 1 (iii)

Misc 1
Find the derivative of the following functions from first principle:
(iii) sin (x + 1)

View solution

Misc 1 (iv)

Misc 1
Find the derivative of the following functions from first principle:
(iv) cos (x−π/8)

View solution

Misc 2

Misc 2 feachoo.com
Find the derivative of the following functions (it is to be
understood that a, b, c, d, p, q, rand s are fixed non-zero
constants and m and n are integers):
(x +a)
Let f(x) = (x + a)
(xty’ = nx? -1
& (a)’=0
where a is constant
f? (x) = 1x1-1+0
=x?
=1

View solution

Misc 3

Misc 3 (Method 1) teachoo.com
Find the derivative of the following functions (it is to be understood
that a, b, c, d, p, q, rand s are fixed non-zero constants and m and n
are integers):
(px + q) ¢ + s)
Let f(x) = (px + q) ¢ + s)
= (px + q) (rx “++ s)
Letu=(pxt+q) &v=(rmt+s)
- f(x) = uv
So, f’(x) = (uvy’
F(x) = uv+ vu Using product rule,
(uv)’ = u’v+v/u

View solution

Misc 4

Misc 4 teachoo.com
Find the derivative of the following functions (it is to be understood
that a, b, c, d, p, q, rand s are fixed non-zero constants and m and
n are integers):
(ax + b) (cx +d)?
Let f(x) = (ax + b) (cx + d)?
Letu=ax+b &v=(cx+d}
So, f(x) = uv
f(x) = (uvy’
=uvtv'u

View solution

Misc 5

feachoo.com
Misc 5
Find the derivative of the following functions (it is to be understood
that a, b, c, d, p, q, rand s are fixed non-zero constants and m and
n are integers): axth
cxtd
Let f(x) = 2 +2
cxt+d
Letu=axtb&v=cx+d
u
ia
“yy = (4%
So, f(x) = (-)
, ulv—vlu
ra

View solution

Misc 6

Misc 6 teackoo.com
Find the derivative of the following functions (it is to be understood
that a, b, c, d, p, q, rand s are fixed non-zero constants and m and n
are integers):
142
x
1 = 1
x
1+2
Let f(x) = 72
x
x+1
__x
= x-1
x
x1 x
=— xX —
x x-1
_xti1
“x4

View solution

Misc 7

Misc 7 feachoo.com
Find the derivative of the following functions (it is to be understood
that a, b, c, d, p, q, rand s are fixed non-zero constants and m and
. 1
n are integers): eabeae
1
Let f(x} = ax’ +bx+c
Letu=1&v=ax? +bx+c
u
ia
yy = (%
So, f(x) = (-)
, ulv—vlu
F(x) = =

View solution

Misc 8

Misc 8 teackoo.com
Find the derivative of the following functions (it is to be understood
that a, b, c, d, p, q, rand s are fixed non-zero constants and m and
n are integers):
ax+b
px’+qxtr
ax+b

Let f(x) = —>———_

pxt+qx+r
Letu=ax+b&v=px? +qx+r

u
f
yy a (Ut

So, f(x) = (¢)

View solution

Misc 9

Misc 9 teackoo.com
Find the derivative of the following functions (it is to be understood
that a, b, c, d, p, q, rand s are fixed non-zero constants and m and
n are integers):
px’+qxtr
ax+b
r+ gx+r
Let f(x) = 22 ="
ax+b
Let u=px?+qx+r&v=axt+b
u

ie u '

So, f(x) = (¢)

View solution

Misc 10

: teachoo.
Misc 10 Paenoo conn
Find the derivative of the following functions (it is to be
understood that a, b, c, d, p, q, rand s are fixed non-zero constants

. b
and m and n are integers): 5 — zat COS X
a b
Let f(x) = ya yet cos x
f(x) = ax-4—bx-? + cos x
f’(x) = (ax -4— bx -2 + cos x)’
= (ax —4)’ — (bx ~2)’ + (cos x)’

Derivative of x" is nx"-1&

Derivative of cos x = —sinx
=a.(-—4)x-4-1 -—b. (-2)x727-14(-sinx)
=—-4ax->+ 2bx-?- sin x
_-—4a 2b .
= +Z ~sinx

View solution

Misc 11

Misc 11 feackoo.com
Find the derivative of the following functions (it is to be understood
that a, b, c, d, p, q, rand s are fixed non-zero constants and m and n
are integers): 4./x -2
Let f(x) = 4/x-2
i
= A(x)2 — 2
i
F(x) = (4(x)2 — 2
(x?) = nxt-t
1, 4-1
= 4.5 (x)? -0 & (a)’=0
a-2 where a is constant
= 2x 2
at
= 2x 2
2
a7
(2
=2
VE

View solution

Misc 12

Misc 12 (Method 1) feachoo.com
Find the derivative of the following functions (it is to be
understood that a, b, c, d, p, g, rand s are fixed non-zero
constants and m and n are integers): (ax + b}"

Let f(x) = (ax + b)".
We know that

, =}; f(x + h) - f(x)
=m SO =

Here, f(x) = {ax + b)"
So, f(x + h) = (a(x + h) + b)"

Putting values

f(x) = lim (a(x+h)+b)” — (ax + by"

hoo h

View solution

Misc 13

feachoo.com

Misc 13
Find the derivative of the following functions (it is to be
understood that a, b, c, d, p, g, rand s are fixed non-zero
constants and m and n are integers): (ax + b)" (cx + d)™
Let f(x) = (ax + b)" (cx +d)"
Let u=(ax+b)"&v=(cx+d)™
f(x) = uv
So, f’ (x) = (uv)’

f’(x) = u’v + v’u

View solution

Misc 14

Misc 14 teachoo.com
Find the derivative of the following functions (it is to be
understood that a, b, c, d, p, q, rand s are fixed non-zero constants
and m and nare integers): sin (x + a}
Let f(x) = sin (x +a)
Using sin (A + B) = sinAcos B +cosB sinA
=sinx.cosa +cosx.sina
= cos a (sin x) + sin a (cos x}
So, f’(x) = (cos a (sin x) + sin a (cos x))’
= (cos a (sin x))’ + (sin a (cos x))’
=cos a (sin x)’+sina(cosx) (cosa & sina is constant)
=cosacosx+sina(—sinx) Derivative of sin x = cos x
Derivative of cos x =—sinx
= cos acos x—sinasinx

View solution

Misc 15

. feachoo.com
Misc 15
Find the derivative of the following functions (it is to be
understood that a, b, c, d, p, g, rand s are fixed non-zero constants
and m and n are integers):

cosec x cot x

Let f(x) = cosec x cot x
Let u=cosecx &v=cotx
So, f(x) = uv
F(x) = (uv)’
Using product rule
f’(x) = u’v+v’u

View solution

Misc 16

. teachoo.
Misc 16 Paenoo conn
Find the derivative of the following functions (it is to be
understood that a, b, c, d, p, q, rand s are fixed non-zero constants
and m and n are integers): Se

1+sin x
Let f (x) = ——*
1+sinx
Let u=cosx &v=1+sinx
u
So, f(x) = >
oa u '
Using quotient rule
’ ulv—vlu
(x) =

View solution

Misc 17

Misc 17 teackoo.com
Find the derivative of the following functions (it is to be
understood that a, b, c, d, p, q, rand s are fixed non-zero constants
and m and n are integers): SDK COS
sin x—cosx
sin x + cos x
Let f (x} = ————————
sin X— cosSx
Letu=sinx+cosx & v=sinx—cosx
u
UL f
So, f’(x) = ()
Using quotient rule

View solution

Misc 18

Misc 18 teackoo.com
Find the derivative of the following functions (it is to be
understood that a, b, c, d, p, q, rand s are fixed non-zero constants
and m and n are integers): secxat
secx+1
secx—-1
Let f (x} = ———_
secxt+1l
Letu=secx-—1&v=secx+1
UuU
CU ta
So, f’(x) = ()
Using quotient rule

View solution

Misc 19

feachoo.com

Misc, 19
Find the derivative of the following functions (it is to be
understood that a, b, c, d, p, g, rand s are fixed non-zero constants
and m and n are integers): sin" x
Let f(x) = sin" x.
Let p =sinx
So,f(x) =p”
By Leibnitz product rule
f(x) = (p"y’ p’

=npr tp’
Putting p = sin x

=nsin"~1x (sin x)’

View solution

Misc 20

. teachoo.
Misc 20 Paenoo conn
Find the derivative of the following functions (it is to be understood
that a, b, c, d, p, q, rand s are fixed non-zero constants and m and n

int ): at+bsinx
are integers): —
at+bsinx
Let f (x) ~~ c+dcosx
Letu=a+bsinx &v=c+dcosx
uu
So, f(x) = ()
- u '
Using quotient rule
, ulv—v'u
P(x) =

View solution

Misc 21

Misc 21 feackoo.com
Find the derivative of the following functions (it is to be understood
that a, b, c, d, p, q, rand s are fixed non-zero constants and m and n
are integers): sins + a)
cosx
Let f (x) = sin(x + a)
cosx
Let u=sin(x+a) &v=cosx
UU
U f
So, f(x) = ()
Using quotient rule
, ulv—v'u
P(x) =

View solution

Misc 22

Misc 22 feachoo.com
Find the derivative of the following functions (it is to be understood
that a, b, c, d, p, q, rand s are fixed non-zero constants and m and n
are integers): x* (5 sin x — 3 cos x)
Let f (x) = x* (5 sin x-— 3 cos x)
Let u=x* &v=5sinx-—3cosx
+ f(x) = uv
So, f’(x) = (uv)!
f'(x)=u'v — vu
Finding uw’ & v’

u=xt

u’ = 4x4-1 (As (x")’ =n x1)

= 43

View solution

Misc 23

feachoo.com

Misc 23
Find the derivative of the following functions (it is to be
understood that a, b, c, d, p, q, rand s are fixed non-zero constants
and m and n are integers): (x + 1) cos x
Let f (x) = 0 +1) cos x
Let u ={x?+ 1) &v=cosx
o f(x} = uv
So, f’(x) = (uv)!
Using product rule

f(x)su'v+ v'u

View solution

Misc 24

Misc 24 teachoo.com
Find the derivative of the following functions (it is to be understood
that a, b, c, d, p, q, rand s are fixed non-zero constants and m and n
are integers):
(ax? + sin x}( p + q cos x)
Let f (x) = (ax? + sin x) (p + q cos x)
Let u=ax’+sinx &v=p+qcosx
- f(x) = uv
So, f’(x) = (uvy’
Using product rule
=u'vt vu

View solution

Misc 25

Misc 25 feachoo.com
Find the derivative of the following functions (it is to be understood
that a, b, c, d, p, q, rand s are fixed non-zero constants and m and n
are integers):
(x + cos x) (x — tan x}
Let f (xj = (x + cos x) (x — tan x)
Let u=x+cosx &v=x-tanx
+ f(x) = uv
So, f’(x) = (uv)’
Using product rule
f'(xj=ulv t+ vu
Finding u’ & v’

View solution

Misc 26

. feachoo.com
Misc 26
Find the derivative of the following functions (it is to be
understood that a, b, c, d, p, q, rand s are fixed non-zero constants
+ 4x+5sinx
and m and n are integers): ————
3x +7 cosx
4x+5sinx
Let f (x) ~ 3x +7 cosx
Letu=4x+5sin &v=3x+7cosx
u
oa u '
So, f (x) = ()
Using quotient rule
, ulv—vlu
P(x) =

View solution

Misc 27

Misc 27 teackoo.com
Find the derivative of the following functions (it is to be understood
that a, b, c, d, p, q, rand s are fixed non-zero constants and m and
. x? cos

n are integers): x.

x? cos=
Let f (x) = ——+

sinx
ris .

Let u =x’ cos > &v=sinx

Uu
So, f(x) = >

Ue t
Using quotient rule

View solution

Misc 28

Misc 28 teackoo.com
Find the derivative of the following functions (it is to be understood
that a, b, c, d, p, q, rand s are fixed non-zero constants and m and
. t ): x

nare integers): ——
Let f (x) = —~—

1+tanx
Letu=x &v=1+tanx

Uu
So, f(x) = >

Ue t
Using quotient rule

View solution

Misc 29

Misc 29 teackoo.com
Find the derivative of the following functions (it is to be
understood that a, b, c, d, p, q, rand s are fixed non-zero constants
and m and n are integers): (x + sec x) (x — tan x)
Let f(x) = (x + sec x) (x — tan x)
Let u=x+secx &v=x-tanx
- f(x) = uv
So, f’(x) = (uvy’
Using product rule
f(x)=ul'v t+ v'u

View solution

Misc 30

Misc 30 teackoo.com
Find the derivative of the following functions (it is to be understood
that a, b, c, d, p, q, rand s are fixed non-zero constants and m and
. x
n are integers): wns
x
Let f(x) = ——
stn x
Letu=x&v=sin"x
Uu
U f
so, r)=(")
0, Fx) = (5
Using quotient rule

View solution

Why Learn This With Teachoo?

Limits and Derivatives introduces the central ideas of calculus. A limit describes the value a function approaches near a point, while a derivative measures instantaneous rate of change and the slope of a tangent. Students evaluate algebraic and trigonometric limits, examine left-hand and right-hand behaviour and find derivatives from first principles or standard formulas. Teachoo provides NCERT solutions, examples, miscellaneous questions and concept-wise lessons for each major method.

What is a limit?

The expression lim x→a f(x) = L means that f(x) can be made arbitrarily close to L by taking x sufficiently close to a, without necessarily requiring x = a. The value f(a) may equal L, differ from L or even be undefined. A limit concerns nearby behaviour.

The left-hand limit, written lim x→a⁻ f(x), examines values of x smaller than a. The right-hand limit, lim x→a⁺ f(x), examines values larger than a. A finite two-sided limit exists only when both one-sided limits exist and are equal. Graphs and piecewise functions make this condition visible.

Direct substitution evaluates many polynomial and rational limits when the denominator remains non-zero. If substitution produces 0/0, the expression is indeterminate—not automatically zero and not proof that the limit does not exist. Algebraic simplification is required.

Methods for evaluating limits

Common methods include factorisation, cancellation, rationalisation and conversion to standard trigonometric limits. When cancelling a factor such as x − a, students use the simplified expression only for x ≠ a; this is sufficient because a limit examines values near a.

Important standard results, with angles measured in radians, include:

  • lim x→0 (sin x)/x = 1;

  • lim x→0 (tan x)/x = 1;

  • lim x→0 (1 − cos x)/x = 0;

  • lim x→a (xⁿ − aⁿ)/(x − a) = naⁿ⁻¹ for suitable positive integers n.

Trigonometric identities and substitutions reduce more complicated expressions to these forms. Students should keep track of constant factors in the argument, for example sin(kx)/x = k·sin(kx)/(kx).

What is a derivative?

The derivative of f at x is defined from first principles by

f′(x) = lim h→0 [f(x + h) − f(x)]/h,

provided the limit exists. At x = a, the derivative f′(a) is the slope of the tangent to y = f(x) at (a, f(a)). It also represents instantaneous rate of change: if position depends on time, its derivative gives instantaneous velocity.

Students derive derivatives of constant, xⁿ, sin x and cos x and then use standard formulas. At this level, the focus is on meaning, first-principle calculation and basic algebra of derivatives. A function may have a value and be continuous-looking yet fail to have a derivative at a sharp corner; derivative existence requires compatible one-sided slopes.

Topics covered on Teachoo

  • Exercises 12.1 and 12.2, examples and miscellaneous questions;

  • intuitive and algebraic definition of a limit;

  • direct substitution and 0/0 forms;

  • polynomial-power limit formulas;

  • limits of trigonometric functions;

  • checking whether a two-sided limit exists;

  • derivative at a point from first principles;

  • derivative at a general point from first principles;

  • derivative of xⁿ by formula;

  • derivatives of sine and cosine;

  • derivatives of other elementary trigonometric expressions.

Core formulas and ideas

  • A two-sided limit exists when left-hand and right-hand limits are equal.

  • 0/0 signals the need for transformation; it is not the final value.

  • f′(a) = lim h→0 [f(a+h) − f(a)]/h.

  • d(c)/dx = 0 for a constant c.

  • d(xⁿ)/dx = nxⁿ⁻¹ for the powers treated in the chapter.

  • d(sin x)/dx = cos x and d(cos x)/dx = −sin x, with x in radians.

  • Differentiation is linear: the derivative of a sum is the sum of derivatives, and constant multiples remain as factors.

Learning outcomes

Students should be able to explain a limit as nearby behaviour, evaluate left-hand and right-hand limits and determine whether a limit exists. They should resolve basic indeterminate forms using algebra or identities. They should calculate derivatives from first principles, use standard derivatives and interpret a derivative as a slope or instantaneous rate.

Why is this chapter important?

Calculus is used to analyse motion, growth, optimisation and change across mathematics, science, economics and engineering. Class 11 Limits and Derivatives forms the direct base for continuity, differentiability, applications of derivatives and integration in Class 12. It is also one of the most important conceptual foundations for JEE.

How Teachoo helps you prepare

Teachoo groups limit questions by direct method, 0/0 factorisation, power formulas, trigonometric limits and existence. Derivatives are separated into first-principle and formula-based methods. This lets students learn the meaning before increasing speed.

For limits, substitute first to diagnose the form. If the result is determinate, stop; if it is 0/0, factor, rationalise or apply an identity. For derivatives from first principles, write f(x + h), subtract f(x), factor out h and only then take the limit. Teachoo’s step-by-step answers make each transformation auditable.

School-exam, JEE and competency preparation

School exams test standard limits, existence and first-principle derivatives. JEE questions combine identities, substitutions, piecewise parameters and derivative interpretation. Do not apply memorised formulas until the expression has the exact required form.

Competency questions may give a graph, position-time relation, cost function or changing measurement. Describe what the limiting or derivative value means with units. A derivative of distance with respect to time has distance-per-time units; the derivative of area with respect to length has area-per-length units.

Quick revision checklist

Evaluate direct-substitution limits, factor three 0/0 forms, rationalise two radical limits, solve trigonometric limits with scaled arguments, compare one-sided limits, find derivatives of x² and x³ from first principles and differentiate a basic polynomial and trigonometric sum.

Common mistakes to avoid

Do not substitute and report 0/0 as the answer. Do not cancel terms across addition; cancellation applies to common factors. Standard trigonometric limits require radians. In first principles, brackets around f(x + h) and f(x) are essential. Do not confuse f′(a) with f(a), and retain the negative sign in the derivative of cosine.

Deeper reasoning and concept connections

A student has understood Limits and Derivatives only when the idea can be moved between words, diagrams, examples and mathematical notation. Start with a concrete example, identify what changes and what remains fixed, represent the relationship clearly and then state the rule. This movement between representations is important because school and competency questions often present a familiar idea in an unfamiliar form.

The chapter should also be connected to earlier and later mathematics. Definitions supply the language, worked examples reveal the method, and mixed questions test whether the method can be selected without a hint. Instead of memorising the appearance of a solved question, ask what information triggered the method, which condition made it valid and how the answer could be checked. That makes learning transferable to later chapters rather than limited to one exercise.

How to solve unfamiliar and competency-based questions

Read the complete problem before calculating. Underline the quantities, conditions and command word—find, compare, construct, justify, estimate or prove. Rephrase the task in one sentence and choose a representation such as a table, labelled figure, number line, expression or graph. Solve in small steps, keeping units and labels visible.

For an application question, the final line must answer the situation, not only display a number. For an assertion–reason question, test the assertion and reason separately before deciding whether one explains the other. For an MCQ, eliminate options using definitions, signs, size estimates or boundary cases before performing long calculations. If the answer is visual, check it against the stated scale or construction conditions rather than the appearance of the drawing.

What complete mastery looks like

For Limits and Derivatives, a student should be able to define the central ideas in simple language, recognise them in different representations, solve routine questions accurately and explain the method used. They should also be able to correct a flawed solution, create an example satisfying given conditions and combine two ideas from the chapter in one problem. A reliable mastery test is to solve one direct question, one application question and one reasoning question without looking at notes, then explain all three aloud or in writing.

Keep a compact error log with four labels: concept, interpretation, calculation and presentation. Reattempt each error after a gap instead of rereading the answer immediately. Improvement comes from correcting the decision that caused the mistake, not from repeating questions whose method is already known.

Additional frequently asked questions

What should a student know before starting Limits and Derivatives?

Revise the definitions, number operations, diagrams or notation used at the beginning of the chapter. The prerequisite list should be short: if an earlier skill blocks progress, repair that skill with two or three focused questions and return to the chapter.

How can a student check an answer in Limits and Derivatives?

Use an independent check whenever possible: substitute the result, reverse the operation, estimate its size, compare it with the figure, test a simpler case or solve using another representation. A check should examine the mathematical condition, not merely repeat the same arithmetic.

How many questions are enough for strong preparation?

There is no fixed number. Stop counting questions and track coverage: every concept, every standard method, at least one mixed problem, one competency-based problem and every previously incorrect type should be solved independently. Ten varied, analysed questions are more valuable than fifty copied solutions.

How should Teachoo solutions be used without becoming dependent on them?

Attempt the question first and mark the exact step where progress stops. Read only enough of the solution to repair that step, close it and restart the question. Finally, solve a similar problem without help. This turns a solution into feedback rather than a substitute for thinking.

Frequently asked questions

Can a limit exist when the function is undefined at the point?

Yes. A limit depends on nearby values, so f(a) need not be defined for lim x→a f(x) to exist.

What does the form 0/0 mean?

It is an indeterminate form indicating that the expression should be simplified or transformed before the limit is evaluated.

When does a two-sided limit exist?

It exists when the left-hand and right-hand limits both exist and are equal.

What does a derivative represent geometrically?

It represents the slope of the tangent to a function’s graph at the point.

Does Teachoo explain derivatives from first principles?

Yes. Teachoo has separate concept sections for derivatives at a point and at a general point using the definition, followed by formula-based questions.

Build calculus from meaning to method. Understanding approach, cancellation and rate of change is more durable than remembering a list of answers.