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Last updated at Nov. 30, 2019 by Teachoo

Transcript

Ex 13.2, 3 Find the derivative of 99x at x = 100 Let f (x) = x We need to find derivative of f(x) at x = 100 i.e. fβ (100) We know that fβ (x) = (πππ)β¬(ββ0)β‘γ(π(π₯ + β) β π (π₯))/βγ Here, f(x) = 99x So, f(x + h) = 99(x + h) = 99x + 99h Putting values fβ (x) = limβ¬(hβ0)β‘γ((99π₯ +99β) β 99π₯)/βγ = limβ¬(hβ0)β‘γ(99π₯ +99β β 99π₯)/βγ = limβ¬(hβ0)β‘γ99β/βγ = limβ¬(hβ0) 99 = 99 Hence, fβ(x) = 99 Putting x = 100 fβ(100) = 99 So, derivative of 99x at x = 100 is 99

Derivatives by 1st principle - At a point

Chapter 13 Class 11 Limits and Derivatives

Concept wise

- Limits - Definition
- Limits - 0/0 form
- Limits - x^n formula
- Limits - Of Trignometric functions
- Limits - Limit exists
- Derivatives by 1st principle - At a point
- Derivatives by 1st principle - At a general point
- Derivatives by formula - x^n formula
- Derivatives by formula - sin & cos
- Derivatives by formula - other trignometric

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.