Last updated at May 4, 2020 by Teachoo

Transcript

Ex 13.1, 18 Evaluate the Given limit: limx→0 ax+x cosxb sinx limx→0 ax + x cosxb sinx = limx→0 x (a + cosx)b sinx = limx→0 (a + cosx) 𝑏 × 𝑥 sin𝑥 = limx→0 (a + cosx) 𝑏÷ sin𝑥𝑥 = limx→0 (a + cosx) 𝑏 ÷ limx→0 sin𝑥𝑥 = limx→0 a + cosx 𝑏 ÷ 1 = limx→0 a + cosx 𝑏 = limx→0 a + cosx 𝑏 Putting x = 0 = 𝑎 + cos0𝑏 = 𝒂 + 𝟏𝒃

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About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.