Ex 7.6, 21 - Chapter 7 Class 12 Integrals

Transcript

Ex 7.6, 21 2 sin I = 2 sin . I = sin . 2 I = sin 2 sin 2 I = sin . 2 2 cos . 2 2 I = 1 2 . 2 sin 1 2 cos . 2 Solving I2 = 1 2 cos . 2 I1 = 1 2 cos . 2 = 1 2 cos 2 cos 2 = 1 2 cos . 2 2 ( sin ) . 2 2 = 1 2 2 . cos 2 + 1 2 2 sin = 1 2 2 . cos 2 + 1 2 I + 1 Putting the value of I1 in (1) , we get I = 2 sin I = 2 sin 2 1 2 2 . cos 2 + I 2 + 1 I = 2 2 sin 2 4 cos I 4 1 + I 4 = 2 sin 2 2 . cos 4 5 4 = 2 4 2 sin cos 1 = 4 5 . 2 4 2 sin cos 4 1 5 = +