Ex 7.6, 4
Last updated at Dec. 8, 2016 by Teachoo
Transcript
Ex 7.6, 4 ๐ฅ logโก๐ฅ โซ1โใ๐ฅ logโก๐ฅ ใ ๐๐ฅ โซ1โใ๐ฅ logโก๐ฅ ใ ๐๐ฅ=โซ1โ(logโก๐ฅ )๐ฅ ๐๐ฅ =logโก๐ฅ โซ1โ๐ฅ ๐๐ฅโโซ1โ(๐(logโก๐ฅ )/๐๐ฅ โซ1โใ๐ฅ.๐๐ฅใ)๐๐ฅ =logโก๐ฅ (๐ฅ^2/2)โโซ1โใ1/๐ฅ . ๐ฅ^2/2. ๐๐ฅใ =ใ๐ฅ^2/2 logใโกใ ๐ฅใโ1/2 โซ1โใ๐ฅ. ๐๐ฅใ =ใ๐ฅ^2/2 logใโก๐ฅโ1/2 . ๐ฅ^2/2 +๐ถ =ใ๐^๐/๐ ๐๐๐ใโกใ ๐ใโ ๐^๐/๐ +๐ช " "
Ex 7.6
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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He provides courses for Mathematics from Class 9 to 12. You can ask questions here.